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3 years ago

What are the similarities and differences between a camera and a camera and the human eye?

2 answers:

kramer3 years ago

7 0

The “screen” in a camera is flat, whereas the retina is curved.
Both eye and camera have limited fields of vision.
Both eye and camera use a transparent convex lens to form an image.
The sensitivity of the eye and the acuity are not constant over the retina, acuity and sensitivity being governed by the distribution of rods and cones on the retina; whereas the sensitivity of the camera film or electronic photosensitive light receptors is distributed evenly.
In a camera only air separates the screen from the lens; the eye is filled with liquid between the lens and the retina and this liquid adds to the refraction of the light.
Blood vessels come in front of the retina and therefore obscure the image, so the eye is in a state of minute motions to compensate for missing parts of the image; in a camera the screen is exposed only for a fraction of second usually to admit the required amount of light to form an image.
In the eye and the camera the lens produces an inverted image.
The eye produces an imperfect image containing chromatic aberration. The lens of a good camera produces minimal chromatic aberration.
The eye is only the start of the vision process and the brain has to learn to translate the image to make it meaningful. The process in the camera is mainly the result of optics directly.
The eye produces a chemical (visual purple) which improves and accommodates vision for different light levels. A camera is more limited for such accommodation. This is noticeable in pictures taken in artificial or low light.
As light level decreases, both eye and camera tend towards monochromatic images.
A camera can be made sensitive to frequencies of light outside the visual range, including ultraviolet and infrared. The eye is limited to a smaller range of light frequencies.
The camera can be used for lengthy exposures while the eye has to operate at a speed dictated by nerve impulses.

Sunny_sXe [5.5K]3 years ago

4 0

So a camera can zoom in and out and the human eye has peripheral vision

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subtract the mass of the filter paper (0.27 g) from the mass of the paper and copper (0.98 g). Record the difference in the data

vova2212 [387]

When measuring copper that is collected on a filter paper, the mass measurement obtained will include both the mass of the filter paper and copper.
therefore we have to find the mass of the empty filter paper before copper is on the paper.
the mass of the filter paper alone is 0.27 g
then the mass of copper and filter paper is 0.98 g
therefore to find the mass of copper alone we have to take the difference between the 2 masses
mass of copper = (mass of copper + filter paper ) - mass of filter paper
= 0.98 g - 0.27 g
mass of copper = 0.71 g

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4 years ago

The standard enthalpy of formation of a free element in its standard

DanielleElmas [232]

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3 years ago

Which subatomic particle has a negative charge in the atom?

natta225 [31]

Answer:

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Explanation:

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3 years ago

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if the reaction occurs in the laboratory and produces 2.8 moles of ammonia, calculate the percent yield for the experiment. Use

Helen [10]

The question is incomplete, here is the complete question:

The Haber process can be used to produce ammonia, $NH_3$ and it is based on the following reaction.

$N_2+3H_2\rightarrow 2NH_3$

If the reaction occurs in the laboratory and 5 moles of each hydrogen and nitrogen gas reacts and produces 2.8 moles of ammonia, calculate the percent yield for the experiment. Use the quantity of the product that is produced by the limiting reagent as the theoretical yield.

<u>Answer:</u> The percent yield of the reaction is 84.08 %.

<u>Explanation:</u>

We are given:

Moles of nitrogen gas = 5 mole

Moles of hydrogen gas = 5 mole

For the given chemical equation:

$N_2+3H_2\rightarrow 2NH_3$

By Stoichiometry of the reaction:

3 moles of hydrogen gas reacts with 1 mole of nitrogen gas

So, 5 mole of hydrogen gas will react with = $\frac{1}{3}\times 5=1.67mol$ of nitrogen gas

As, given amount of nitrogen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, hydrogen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

3 moles of hydrogen gas produces 2 moles of ammonia

So, 5 moles of hydrogen gas will produce = $\frac{2}{3}\times 5=3.33mol$ of ammonia

To calculate the percentage yield of ammonia, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of ammonia = 2.8 moles

Theoretical yield of ammonia = 3.33 moles

Putting values in above equation, we get:

$\%\text{ yield of ammonia}=\frac{2.8mol}{3.33mol}\times 100\\\\\% \text{yield of ammonia}=84.08\%$

Hence, the percent yield of the reaction is 84.08 %.

8 0

3 years ago

The heat gained by the ice melted the ice and raised the temperature of the melted ice from its initial temperature to the final

liberstina [14]

Answer:

True

Explanation:

When ice is heated, the ice gains heat.

This heat gained by the ice is both used to break the intermolecular forces in ice to form water, as well as to raise the temperature of the water to it's final temperature.

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3 years ago