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3 years ago

What are the similarities and differences between a camera and a camera and the human eye?

2 answers:

kramer3 years ago

7 0

The “screen” in a camera is flat, whereas the retina is curved.
Both eye and camera have limited fields of vision.
Both eye and camera use a transparent convex lens to form an image.
The sensitivity of the eye and the acuity are not constant over the retina, acuity and sensitivity being governed by the distribution of rods and cones on the retina; whereas the sensitivity of the camera film or electronic photosensitive light receptors is distributed evenly.
In a camera only air separates the screen from the lens; the eye is filled with liquid between the lens and the retina and this liquid adds to the refraction of the light.
Blood vessels come in front of the retina and therefore obscure the image, so the eye is in a state of minute motions to compensate for missing parts of the image; in a camera the screen is exposed only for a fraction of second usually to admit the required amount of light to form an image.
In the eye and the camera the lens produces an inverted image.
The eye produces an imperfect image containing chromatic aberration. The lens of a good camera produces minimal chromatic aberration.
The eye is only the start of the vision process and the brain has to learn to translate the image to make it meaningful. The process in the camera is mainly the result of optics directly.
The eye produces a chemical (visual purple) which improves and accommodates vision for different light levels. A camera is more limited for such accommodation. This is noticeable in pictures taken in artificial or low light.
As light level decreases, both eye and camera tend towards monochromatic images.
A camera can be made sensitive to frequencies of light outside the visual range, including ultraviolet and infrared. The eye is limited to a smaller range of light frequencies.
The camera can be used for lengthy exposures while the eye has to operate at a speed dictated by nerve impulses.

Sunny_sXe [5.5K]3 years ago

4 0

So a camera can zoom in and out and the human eye has peripheral vision

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When C2H6(g) reacts with O2(g) according to the following reaction, 1.43×103 kJ of energy are evolved for each mole of C2H6(g) t

dezoksy [38]

Answer:

-2.86x10³ kJ

Explanation:

The enthalpy of a reaction (ΔH) is defined as the heat produced or consumed by a reaction. In the reaction:

2 C₂H₆(g) + 7 O₂(g) → 4 CO₂(g) + 6 H₂O(g)

The ΔH is the heat envolved in the reaction per 2 moles of C₂H₆. 1.43x10³ kJ are involved when 1 mole reacts. Thus, when 2 moles react, involved heat is:

1.43x10³ kJ ₓ 2 = 2.86x10³ kJ. As the reaction is a combustion reaction (Produce CO₂ and H₂O), the heat involved in the reaction is PRODUCED, that means ΔH is negative, -2.86x10³ kJ

8 0

3 years ago

Write a balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air.

Lelechka [254]

Answer: The balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is $CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O$ .

Explanation:

When a substance tends to gain oxygen atom in a chemical reaction and loses hydrogen atom then it is called oxidation reaction.

For example, chemical equation for oxidation of methane is as follows.

$CH_{4} + O_{2} \rightarrow CO_{2} + H_{2}O$

Number of atoms present on reactant side are as follows.

C = 1
H = 4
O = 2

Number of atoms present on product side are as follows.

C = 1
H = 2
O = 3

To balance this equation, multiply $O_{2}$ by 2 on reactant side. Also, multiply $H_{2}O$ by 2 on product side. Hence, the equation can be rewritten as follows.

$CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O$

Now, the number of atoms present on reactant side are as follows.

C = 1
H = 4
O = 4

Number of atoms present on product side are as follows.

C = 1
H = 4
O = 4

Since, the atoms present on both reactant and product side are equal. Therefore, this equation is now balanced.

Thus, we can conclude that balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is $CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O$ .

4 0

3 years ago

How many molecules of water are there in 1 gram of water

alisha [4.7K]

Answer:

6.022*1023

Explanation:

3 0

3 years ago

Read 2 more answers

Provide the name of the compound shown below. Spelling and format counts! CH3 NO2 NO2

lesantik [10]

Answer:

ch3:-methanide

No2:-nitrogen dioxide

thank you and mark as brainliest if u find it helpful

4 0

3 years ago

Draw a reaction energy profile (energy vs dihedral angle) for rotation about the c-c bond in ethane. Show the Newman projections

astraxan [27]

Answer:

The energy profile for rotation about the C-C bond in ethane is shown in the image, along with the Newman projections of the corresponding ethane conformer.

Explanation:

If you see the ethane molecule (second image) from the C-C bond axis (third image), as in the Newman projections, it's easy to draw an angle between one of the hydrogen atoms of the visible carbon, the carbon itself, and one of the hydrogens of the hidden carbon.

When you make a rotation about the C-C bond, the angle between those hydrogens will change. If you start with an eclipsed conformation, with each hydrogen of the hidden C exactly behind the hydrogens of the visible C, the angle will be 0°, or also 120° or 240°, as this rotations will be equivalent. On the other hand, if the angle is 60° (or 180°, or 300°), you will have a staggered conformation. The eclipsed conformation is less stable than the staggered one, because the interactions between hydrogens will be bigger (the repulsion between their electrons), and because of that the eclipsed conformations will be found in the maxima, while the staggered one will be found in the minima.

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3 years ago