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Rasek [7]
3 years ago
8

An order is given to administer methylprednisolone, an anti-inflammatory drug, by IV at a rate of 39 mg every 30 min. The IV bag

contains 125 mg of methylprednisolone in every 2 mL. What should the flow rate be in milliliters per minute (mL/min)? flow rate=_______ mL/min
Chemistry
1 answer:
Korvikt [17]3 years ago
3 0

Answer:

The Flow rate = 0.0208 mL/min

Explanation:

Data provided:

Rate of dose = 39 mg every 30 min = (39/30) mg/min  = 1.3 mg/min

also,

125mg of methylprednisolone is present in every 2 mL

thus,

concentration = (125/2) mg/mL = 62.5 mg/mL

Now,

The flow rate is given as:

Flow rate = Rate / Concentration

on substituting the respective values, we get

Flow rate = (1.3 mg/min) / (62.5mg/mL)

or

The Flow rate = 0.0208 mL/min

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You are on the Titanic and want to find something that will float because you didn't
damaskus [11]

Find volume of pillow

L=78cm

B=55cm

H=25cm

\\ \bull\tt\longrightarrow V=LBH

\\ \bull\tt\longrightarrow V=25(78)(55)

\\ \bull\tt\longrightarrow V=107250cm^3

\\ \bull\tt\longrightarrow V=10.72m^3

Now

Mass=5.5kg

\\ \bull\tt\longrightarrow Density=\dfrac{Mass}{Volume}

\\ \bull\tt\longrightarrow Density=\dfrac{5.5}{10.72}

\\ \bull\tt\longrightarrow Density=0.5kg/m^3

Density of water=1000kg/m^3

As it is less than density of water it will float on water

8 0
2 years ago
When a nonmetal bonds with a nonmetal, they form a(n)
seropon [69]
Covalent bonds would be formed when a non-metal bonds with another non-metal 
6 0
3 years ago
12.25ml of significant digits
Troyanec [42]

Answer:

4 significant figures

Explanation:

____

4 0
2 years ago
Write the formula of the conjugate base of the Brønsted-Lowry acic, HF​
alexdok [17]

Answer:

Furthermore, because hydrofluoric acid, HF, loses a proton, H+1, to generate its conjugate in the reaction that is shown above, this reactant can be classified as a Brønsted-Lowry acid, and, consequently, the fluoride ion, F–1, is the conjugate base of this acid.

Explanation:

hope this helps

5 0
3 years ago
What is the mass, in grams, of solute in 255mL of a 0.0525M solution of KMnO4 (MM =
Murljashka [212]

Answer:

Mass = 2.12 g

Explanation:

Given data:

Volume of KMnO₄ = 255 mL (255/1000 = 0.255 L)

Molarity = 0.0525 M

Mass in gram = ?

Solution:

First of all we will calculate the number of moles.

<em>Molarity = number of moles of solute / volume in litter</em>

0.0525 M = number of moles of solute / 0.255 L

Number of moles of solute = 0.0525 M ×0.255 L

Number of moles of solute = 0.0134 mol

Mass in gram:

<em>Number of moles = mass/ molar mass</em>

Mass = moles × molar mass

Mass = 0.0134 mol × 158.04 g/mol

Mass = 2.12 g

4 0
3 years ago
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