A woman falls to the ground while wearing a parachute. The air resistance on the parachute of the parachute is 500N. If the woma
2 answers:
The fact that the woman falls at a constant velocity means its acceleration is zero.
For Newton's second law, the resultant of the forces acting on a body is equal to the product between the mass m of the body and its acceleration a:
In our problem, the acceleration is zero, so the resultant of the forces should be zero as well.
Only two forces are acting on the woman: the air resistance R (upward, 500 N) and the weight W (downward). The resultant of these two forces is zero, so
and since the air resistance R is 500 N, then the weight (the gravitational force) of the woman is 500 N as well.
For Newton's second law, the resultant of the forces acting on a body is equal to the product between the mass m of the body and its acceleration a:
In our problem, the acceleration is zero, so the resultant of the forces should be zero as well.
Only two forces are acting on the woman: the air resistance R (upward, 500 N) and the weight W (downward). The resultant of these two forces is zero, so
and since the air resistance R is 500 N, then the weight (the gravitational force) of the woman is 500 N as well.
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Answer:d
Explanation:
Given
Magnitude of Vector A is 3 m
and Magnitude of vector B is 4 m
So the maximum value of resultant can be 7 m when both are at an angle of
and its minimum value can be 1 m when both are at angle of
So the resultant must lie between 1 m to 7 m