Complete Question
The complete question is shown on the first uploaded image
Answer:
The value is 
Explanation:
Generally for an n-type semiconductor the current density is mathematically represented as

Here
is mathematically represented as

=> 
=> 
So

From the diagram 
=> 
So


So from 
substitute
for q and
and from the diagram
So


To solve the problem it is necessary to identify the equation in the manner given above.
This equation corresponds to the displacement of a body under the principle of simple harmonic movement.
Where,

PART A) Our equation corresponds to

Therefore the value of omega is equivalent to that of

From the definition we know that the period as a function of angular velocity is equivalent to



This same point is the equivalent of the maximum point of the speed that the body can reach, since the internal expression of the
Is equivalent to . So the maximum speed that the body can reach is,



Therefore the maximum felocity will be 5ft / s
PART B) The period of graph is the time taken to reach from one maximum point to next point maximum point, then


football hemets have pads that are filled with air and thick foam so when they are hit the foam asorbs the hit and the air keeps the hard outer shell of the helmet from hiting the players head
Gregor Mendel was the first person to trace the characteristics of successive generations of a living thing.