I would help them out and try to comfort and protect them from what was making them feel like that
Answer:
1.6×10⁻⁶ N.
Explanation:
From the question,
F = (V/r)q......................... Equation 1
Where F = Electric force on the raindrop, V = Potential difference between the base of the cloud and the ground, r = distance between the base of the cloud and the ground, q = the charge on a rain drop.
Given: V = 200MV = 200×10⁶ V, r = 500 m, q = 4.0×10⁻¹² C.
Substitute these values into equation 1
F = [(200×10⁶ )/500]×4.0×10⁻¹²
F = 1.6×10⁻⁶ N.
Answer:
The minimum angular speed 57.0 rad/s
Explanation:
In this exercise we must use the relationships between the angular and linear magnitudes, for the speeds we have
v = w r
As they give us that linear velocity is constant, we will calculate the angular velocity for the two radii, external and internal
r1 = 11.75 cm (1 m / 100cm) = 0.1175 m
w1 = v / r1
w1 = 6.70 / 0.1175
w1 = 57.0 rd / s
R2 = 4.50 cm = 0.0450 m
w2 = 6.70 / 0.0450
w2 = 148 rad / s
The minimum angular speed 57.0 rad / s
Answer:
3 volts
Explanation:
It is given that,
Magnetic field, B = 0.8 T
Length of a conducting rod, l = 50 cm = 0.5 m
Velocity of the conducting rod, v = 7.5 m/s
We need to find the magnitude of the emf induced in the rod when it is moving toward the right. When a rod is moved in a magnetic field, an emf is induced in it and it is given by :
Putting all the values,
So, the magnitude of the emf induced in the rod is 3 volts.
By the help of newtons law of gravitation we can derive keplers third law of planetary motion.
