Which elements are found in all four components of Earth?

Please help on any part you can. I know it is a lot but any help I’d greatly appreciate. I attempted the problem but still do no

Alika [10]

Answer:

Please help on any part you can. I know it is a lot but any help I’d greatly appreciate. I attempted the problem but still do not understand. Thank you so much!

Explanation:

Please help on any part you can. I know it is a lot but any help I’d greatly appreciate. I attempted the problem but still do not understand. Thank you so much!

$\boxed{lol}$

7 0

3 years ago

Check the correctness of formula t=2π √m/k, dimensionally

pantera1 [17]

Hi there! Lets see!

m is mass, and its units are kg
k is the elastic constant measured in newtons per meter (N/m), or kilograms per second squared kg/s²

Therefore:

$\sqrt{\dfrac{m}{k}} =\sqrt{\dfrac{[kg]}{[\dfrac{kg}{s^2}]}} =\sqrt{\dfrac{[kg]}{[kg]}\cdot s^2} = \sqrt{[s]^2} = s$

The period is given in seconds so the formula is dimensionally correct.

4 0

3 years ago

If an object has a net positive charge of 4.0 coulombs, the object possesses (1) 6.3 × 10^18 more electrons than protons (2) 2.5

Readme [11.4K]

Answer:

(4) $2.5 \times 10^{19}$ more protons than electrons

Explanation:

Total positive change on the object is given as

$Q = 4 C$

now by the law of quantization of charge we know that the charge on any body is always in form of integral multiple of charge of an electron.

So we will have

$Q = N e$

here we know that

$4 = N(1.6 \times 10^{-19})$

$N = 2.5 \times 10^{19}$

Now we know that the object is positively charged so here electrons must be less in numbers than protons

so correct answer will be

(4) $2.5 \times 10^{19}$ more protons than electrons

3 0

4 years ago

What causes the phenomena?

Murrr4er [49]

Answer:

Most pneumonia occurs when a breakdown in your body's natural defenses allows germs to invade and multiply within your lungs.

Explanation:

7 0

3 years ago

A rugby player sits on a scrum machine that weighs 200 Newtons. Given that the coefficient of static friction is 0.67, the coeff

Trava [24]

a. 850 N is the minimum force needed to get the machine/player system moving, which means this is the maximum magnitude of static friction between the system and the surface they stand on.

By Newton's second law, at the moment right before the system starts to move,

• net horizontal force

∑ F[h] = F[push] - F[s. friction] = 0

• net vertical force

∑ F[v] = F[normal] - F[weight] = 0

and we have

F[s. friction] = µ[s] F[normal]

It follows that

F[weight] = F[normal] = (850 N) / (0.67) = 1268.66 N

where F[weight] is the combined weight of the player and machine. We're given the machine's weight is 200 N, so the player weighs 1068.66 N and hence has a mass of

(1068.66 N) / g ≈ 110 kg

b. To keep the system moving at a constant speed, the second-law equations from part (a) change only slightly to

∑ F[h] = F[push] - F[k. friction] = 0

∑ F[v] = F[normal] - F[weight] = 0

so that

F[k. friction] = µ[k] F[normal] = 0.56 (1268.66 N) = 710.45 N

and so the minimum force needed to keep the system moving is

F[push] = 710.45 N ≈ 710 N

4 0

2 years ago

Which elements are found in all four components of Earth?​

Which elements are found in all four components of Earth?