<span>MM = [(2.15)(0.08206)(344)]/[(1.1)(1.75)] = 31.53 g/mol
Remember to convert temperature to Kelvin.</span>
Answer:
1.32 mole
Explanation:
The following data were obtained from the question:
Volume of solution = 2.2L
Molarity of solution = 0.60M
Mole of Li3PO4 =..?
Molarity is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is represented as:
Molarity = mole /Volume
With the above formula we can easily calculate the number of mole of Li3PO4 as shown below:
Molarity =mole /Volume
0.6 = mole of Li3PO4 /2.2
Cross multiply
Mole of Li3PO4 = 0.6 x 2.2
Mole of Li3PO4 = 1.32 mole
Therefore, 1.32 mole of Li3PO4 is contained in the solution.
454 teraHz I think, tell me if this is wrong
Answer: 72.4 kJ/mol
Explanation:
The balanced chemical reaction is,
The expression for enthalpy change is,
![\Delta H=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H_f%28product%29%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H_f%28reactant%29%5D)
![\Delta H=[(n_{CO_2}\times \Delta H_{CO_2})+(n_{H_2O}\times \Delta H_{H_2O})]-[(n_{O_2}\times \Delta H_{O_2})+(n_{C_3H_8}\times \Delta H_{C_3H_8})]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5B%28n_%7BCO_2%7D%5Ctimes%20%5CDelta%20H_%7BCO_2%7D%29%2B%28n_%7BH_2O%7D%5Ctimes%20%5CDelta%20H_%7BH_2O%7D%29%5D-%5B%28n_%7BO_2%7D%5Ctimes%20%5CDelta%20H_%7BO_2%7D%29%2B%28n_%7BC_3H_8%7D%5Ctimes%20%5CDelta%20H_%7BC_3H_8%7D%29%5D)
where,
n = number of moles
(as heat of formation of substances in their standard state is zero
Now put all the given values in this expression, we get
![-2220.1=[(3\times -393.5)+(4\times -241.8)]-[(5\times 0)+(1\times \Delta H_{C_3H_8})]](https://tex.z-dn.net/?f=-2220.1%3D%5B%283%5Ctimes%20-393.5%29%2B%284%5Ctimes%20-241.8%29%5D-%5B%285%5Ctimes%200%29%2B%281%5Ctimes%20%5CDelta%20H_%7BC_3H_8%7D%29%5D)
Therefore, the heat of formation of propane is 72.4 kJ/mol
Answer:
c
Explanation:
the conponents are in the line going down and the OH on the right down
