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2 years ago

Which intermolecular force would affect melting point the most?

Chemistry

1 answer:

Anastaziya [24]2 years ago

3 0

Answer:

Hydrogen bonding

Explanation:

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How many moles of KMnO, are in 66.38 g of KMnO?

schepotkina [342]

Answer:.603moles

Explanation:do given over 1 so 66.38 over 1 then multiply by 1 over 110.035344(the atomic mass of KMnO) and then you get the answear

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2 years ago

The vapor pressure of substance X is 100. mm Hg at 1080.°C. The vapor pressure of substance X increases to 600. mm Hg at 1220.°C

artcher [175]

Explanation:

The given data is as follows.

$P_{1}$ = 100 mm Hg or $\frac{100}{760}atm$ = 0.13157 atm

$T_{1}$ = $1080 ^{o}C$ = (1080 + 273) K = 1357 K

$T_{2}$ = $1220 ^{o}C$ = (1220 + 273) K = 1493 K

$P_{2}$ = 600 mm Hg or $\frac{600}{760}atm$ = 0.7895 atm

R = 8.314 J/K mol

According to Clasius-Clapeyron equation,

$log(\frac{P_{2}}{P_{1}}) = \frac{\Delta H_{vap}}{2.303R}[\frac{1}{T_{1}} - \frac{1}{T_{2}}$

$log(\frac{0.7895}{0.13157}) = \frac{\Delta H_{vap}}{2.303 \times 8.314 J/mol K}[\frac{1}{1357 K} - \frac{1}{1493 K}]$

$log (6) = \frac{\Delta H_{vap}}{19.147}[\frac{(1493 - 1357) K}{1493 K \times 1357 K}]$

0.77815 = $\frac{\Delta H_{vap}}{19.147J/K mol} \times 6.713 \times 10^{-5} K$

$\Delta H_{vap}$ = $2.219 \times 10^{5}$ J/mol

= $2.219 \times 10^{5}J/mol \times 10^{-3}\frac{kJ}{1 J}$

= 221.9 kJ/mol

Thus, we can conclude that molar heat of vaporization of substance X is 221.9 kJ/mol.

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2 years ago

What type of molecule is shown below?

stealth61 [152]

The type of molecule that is shown is D. Alcohol

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3 years ago

When the oxidation number of an element decreases over the course of a reaction, that element has beenWhich of the following che

NARA [144]

AgNO3+NaCl yields AgCl+NaNo3 (reduction)
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3 years ago

This formula equation is unbalanced. Pb(NO3)2(aq) + Li2SO4(aq)--> PbSO4(s) + LiNO3(aq). Which coefficient should appear in fr

Temka [501]

<span>Balancing is making sure there are the same number of atoms on either side of the reaction.

Pb(NO3)2 + Li2SO4--> PbSO4 + LiNO3

There are 2 NO3 groups and 2 Li on the right side, need 2 on the left side.
Need a coefficient of 2 for LiNO3
</span>

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3 years ago

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