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VashaNatasha [74]
3 years ago
10

Water acts as a(n) _____. solvent solute organic substance ionic compound

Chemistry
2 answers:
siniylev [52]3 years ago
8 0

Answer: solvent

Explanation:

Solute is the component which is present in smaller proportion and is solid for solid in liquid solution. Example: sugar in sugar solution.

Solvent is the component which is present in larger proportion and is liquid for solid in liquid solution.Example: water in sugar solution.

Organic compounds are those compounds that contain carbon bonded to hydrogen.

Ionic compound is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element and the element which accepts the electrons is known as electronegative element.

viktelen [127]3 years ago
4 0
Solvent because it is water and it coudent be solute
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Acetone (nail polish remover) has a density of 0.7857 g &gt;cm3.
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If acetone has a density of 0.7857 \frac{g}{cm^{3} }  the mass in grams of point A is 22.4 g and the volume at point B is 8.32 mL.

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What does electronegativity measure
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Unit: Chemical Quantities
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Answer:

(See explanation for further details)

Explanation:

1) The quantity of moles of sulfur is:

n = \frac{1.20\times 10^{24}\,atoms}{6.022\times 10^{23}\,\frac{atoms}{mol} }

n = 1.993\,moles

2) The number of atoms of helium is:

x = (1.5\,moles)\cdot \left(6.022\times 10^{23}\,\frac{atoms}{mole} \right)

x = 9.033\times 10^{23}\,atoms

3) The quantity of moles of carbon monoxide is:

n = \frac{4.15\times 10^{23}\,molecules}{6.022\times 10^{23}\,\frac{molecules}{mol} }

n = 0.689\,moles

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x = (2.25\,moles)\cdot \left(6.022\times 10^{23}\,\frac{molecules}{mole} \right)

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5) The quantity of moles of sodium chloride is:

n = \frac{2.4\times 10^{23}\,molecules}{6.022\times 10^{23}\,\frac{molecules}{mol} }

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x = (1.8\,moles)\cdot \left(6.022\times 10^{23}\,\frac{f.u.}{mole} \right)

x = 1.084\times 10^{24}\,f.u.

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n = \frac{3.67\times 10^{23}\,f.u.}{6.022\times 10^{23}\,\frac{f.u.}{mol} }

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x = (0.25\,moles)\cdot \left(6.022\times 10^{23}\,\frac{molecules}{mole} \right)

x = 1.506\times 10^{23}\,molecules

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x = (3.52\,moles)\cdot \left(6.022\times 10^{23}\,\frac{molecules}{mole} \right)

x = 2.120\times 10^{24}\,molecules

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