All categories

3 years ago

Find two consecutive integers whose sum is 73. Which of the following equations could be used to solve the problem?

Mathematics

2 answers:

max2010maxim [7]3 years ago

8 0

2x + 1 = 73

2x = 72
x = 36

the 2 integers are 36 and 37

Its b

Brrunno [24]3 years ago

4 0

Answer:

b: 2x + 1 = 73

Step-by-step explanation:

Let x be the smaller integer,

Then the larger integer consecutive to x is x + 1,

Sum of these integers = x + x + 1 = 2x + 1

According to the question,

The sum is 73

⇒ 2x + 1 = 73

Which is the required equation that could be used to solve the problem.

Option 'b' is correct.

You might be interested in

Only the a) part please!!!!

choli [55]

$(i)\\\\2A = \begin{pmatrix}3x \times 2 & 1 \times 2 & 5 \times 2\\0\times 2 & 2x \times 2 & -3 \times 2\end{pmatrix} = \begin{pmatrix}6x & 2 & 10\\0 & 4x & -6\end{pmatrix}\\\\\\(ii)\\\\2A + B = C\\\\\implies \begin{pmatrix}6x & 2 & 10\\0 & 4x & -6\end{pmatrix} + \begin{pmatrix}y & 0 & -4\\1 & -3y & 2\end{pmatrix} = \begin{pmatrix}31& 2 & 6\\1 & 17& -4\end{pmatrix}$

$\implies \begin{pmatrix}6x+y & 2+0 & 10-4\\0+1 & 4x-3y & -6+2\end{pmatrix} = \begin{pmatrix}31 & 2 & 6\\1 & 17& -4 \end{pmatrix}\\\\\\\implies \begin{pmatrix}6x+y & 2 & 6\\1 & 4x-3y & -4\end{pmatrix} = \begin{pmatrix}31 & 2 & 6\\1 & 17& -4 \end{pmatrix}\\\\\text{System of equations},\\\\6x +y =31,~~ 4x -3y = 17\\\\\\(iii)\\\\6x +y-31 =0 \\\\4x-3y -17=0\\\\\text{Solving by cross multiplication method}\\\\\\\dfrac x{1(-17) - (-31)(-3)} = \dfrac y{4(-31) - 6(-17)} = \dfrac 1{6(-3) - 4(1)}$

$\implies \dfrac{x}{-17 -93} = \dfrac{y}{-124 +102} = \dfrac 1{-18-4}\\\\\\\implies -\dfrac{x}{110} = -\dfrac{y}{22} = -\dfrac 1{22}\\\\ \implies \dfrac{x}{110} = \dfrac{y}{22} = \dfrac 1{22}\\\ \\\text{Hence,}\\\\\\x=\dfrac{110}{22}=5,~~~~ y= \dfrac{22}{22} =1$

7 0

2 years ago

Read 2 more answers

If 2x• 3x +(2•3 )x +6x= 648, find x.

klasskru [66]

Answer:

x = -1 ± √109

Step-by-step explanation:

2x • 3x + (2 • 3)x + 6x = 648

According to PEMDAS (parentheses/exponents | multiplication/division | addition/subtraction), we should solve the parentheses first.

(2 • 3) = 6

Now we have:

2x • 3x + (6)x + 6x = 648

Now let's multiply.

2x • 3x = 6x²

6 • x = 6x

Now we have.

6x² + 6x + 6x = 648

Combine like terms.

6x² + 12x = 648

Let's factor out a 6.

6(x² + 2x) = 648

Divide both sides by 6.

x² + 2x = 108

Let's use completing the square.

Our equation is in a² + bx = c form.

Divide b by 2.

2/2 = 1

Then square it.

1² = 1

Add 1 to both sides.

x² + 2x + 1 = 108 + 1

Simplify.

x² + 2x + 1 = 109

Now we want to factor the left side. A shortcut is just to use b/2.

(x + 1)² = 109

Take the square root of both sides.

x + 1 = ±√109

The square root is as simplified as possible.

Subtract 1 from both sides.

x = -1 ± √109

Hope this helps!

4 0

3 years ago

Read 2 more answers

Help math problem please anyone

kondor19780726 [428]

1/15 is how much further it is

8 0

3 years ago

Read 2 more answers

A=9,b=-24 <br> Evaluate a +b for the given valus

aliina [53]

Step-by-step explanation:

A + b

Putting value of a and b

9 + (-24)

9 - 24

= - 15

7 0

3 years ago

an electronics store sells large flat screen tvs for 1699 last month the store sold 8 of this tvs anout how much did the tvs sel

rusak2 [61]

The answer is $212.37 for each large flatscreen tv

4 0

3 years ago