Proportionately, the amount of the drug that the patient should be given is <u>2,993.71 mg</u>.
<h3>What is the proportion?</h3>
The proportion is the ratio of a variable to another.
Proportion defines the numerical relationships among variables.
Proportion shows how much a value is contained in the whole.
<h3>Data and Calculations:</h3>
2.20462 lb = 1 kg
165 lb = 74.8428 kg (165/2.20462)
1 kg = 40 mg of the drug
74.8428 kg = 2,993.71 mg (74.8428 kg x 40 mg)
Thus, the amount of the drug that the patient should be given is <u>2,993.71 mg</u>.
Learn more about proportions at brainly.com/question/870035
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Answer:
<h2>3000 pcs</h2>
Step-by-step explanation:
given:
the Length, breadth and height of a wall is 5m,30cm and 3 m
find:
how many bricks of dimensions 20cm ×10 cm× 7.5 cm are required to build the wall
solution:
vol of the wall = 5 x 3 x 0.30= 4.5 m³
vol per brick = 0.20 x 0.10 x 0.075 = 0.0015 m³
number of bricks = <u> wall volume </u>
vol. per brick
= 4.5 / 0.0015
= 3000 pcs of bricks required
Answer:
480 inches squared
Step-by-step explanation:
The formula for the area of a rhombus is pq/2, where p and q are the diagonals. In the picture, half of a diagonal is 10 (which I am assuming 10 does not represent the whole diagonal), so all of the horizontal diagonal is 20.
Applying the Pythagorean Theorem to this, we get 10^2 + x^2 = 26^2. After simplifying, this becomes 100 + x^2 = 676, and therefore x = 24. Multiply this by 2 to get the full vertical diagonal, the area is simply 48*20/2 which is 480 inches squared.
![\bf 2sin(x)cos(x)=sin(x)\sqrt{2}\implies 2sin(x)cos(x)-sin(x)\sqrt{2}=0 \\\\\\ sin(x)~[2cos(x)-\sqrt{2}]=0\\\\ -------------------------------\\\\ sin(x)=0\implies \measuredangle x=0~~,~~\pi \\\\ -------------------------------\\\\ 2cos(x)-\sqrt{2}=0\implies 2cos(x)=\sqrt{2}\implies cos(x)=\cfrac{\sqrt{2}}{2} \\\\\\ \measuredangle x=\frac{\pi }{4}~~,~~\frac{7\pi }{4}](https://tex.z-dn.net/?f=%5Cbf%202sin%28x%29cos%28x%29%3Dsin%28x%29%5Csqrt%7B2%7D%5Cimplies%202sin%28x%29cos%28x%29-sin%28x%29%5Csqrt%7B2%7D%3D0%0A%5C%5C%5C%5C%5C%5C%0Asin%28x%29~%5B2cos%28x%29-%5Csqrt%7B2%7D%5D%3D0%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0Asin%28x%29%3D0%5Cimplies%20%5Cmeasuredangle%20x%3D0~~%2C~~%5Cpi%20%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0A2cos%28x%29-%5Csqrt%7B2%7D%3D0%5Cimplies%202cos%28x%29%3D%5Csqrt%7B2%7D%5Cimplies%20cos%28x%29%3D%5Ccfrac%7B%5Csqrt%7B2%7D%7D%7B2%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Cmeasuredangle%20x%3D%5Cfrac%7B%5Cpi%20%7D%7B4%7D~~%2C~~%5Cfrac%7B7%5Cpi%20%7D%7B4%7D)
now, we're not including the III and II quadrants, where the cosine has an angle of the same value, but is negative, because the exercise seems to be excluding the negative values of √(2).
