Drag the genotypes and phenotypes from the left to correctly complete the punnett square for the f2 generation. drag only blue l
abels to blue targets and pink labels to pink targets. labels may be used more than once.
1 answer:
I found the exercise on the internet. Attached is the Punnett square and the labels to place in it.
For the spot (a), place the blue label "GG" because that square is correspondent to the combination of the alleles G and G from both parents. For the spot (b), place the pink label with a green pod because green is the dominant trait as both parents are heterozygous and present green colour.
For the spot (c), place the blue label "Gg" because that square is correspondent to the combination of the allele G from an egg and the allele g from the sperm. For the spot (d), place the pink label with a green pod because green is the dominant trait as both parents are heterozygous (as well as this genotype) and present green colour.
For the spot (e), place the blue label "Gg" because that square is correspondent to the combination of the allele g from an egg and the allele G from the sperm. For the spot (f), place the pink label with a green pod because green is the dominant trait as both parents are heterozygous (as well as this genotype) and present green colour.
For the spot (g), place the blue label "gg" because that square is correspondent to the combination of the alleles g and g from both parents. For the spot (h), place the pink label with a yellow pod because yellow is the recessive trait as both parents are heterozygous and present green colour.
For the spot (a), place the blue label "GG" because that square is correspondent to the combination of the alleles G and G from both parents. For the spot (b), place the pink label with a green pod because green is the dominant trait as both parents are heterozygous and present green colour.
For the spot (c), place the blue label "Gg" because that square is correspondent to the combination of the allele G from an egg and the allele g from the sperm. For the spot (d), place the pink label with a green pod because green is the dominant trait as both parents are heterozygous (as well as this genotype) and present green colour.
For the spot (e), place the blue label "Gg" because that square is correspondent to the combination of the allele g from an egg and the allele G from the sperm. For the spot (f), place the pink label with a green pod because green is the dominant trait as both parents are heterozygous (as well as this genotype) and present green colour.
For the spot (g), place the blue label "gg" because that square is correspondent to the combination of the alleles g and g from both parents. For the spot (h), place the pink label with a yellow pod because yellow is the recessive trait as both parents are heterozygous and present green colour.
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Answer:
This question is incomplete, the complete question is:
Two fruit flies that are heterozygous for body color and eye color are crossed. Brown body color is dominant to black body color. Red eye color is dominant to brown eye color. Use the Punnett square to determine the ratio of offspring with: Brown body and red eyes : Brown body and brown eyes : Black body and red eyes : Black body and brown eyes :
The answer is:
Brown body and red eyes : 9
Brown body and brown eyes : 3 Black body and red eyes : 3 Black body and brown eyes : 1
Explanation:
This question is a typical dihybrid cross involving two different genes. One coding for body color and the other for eye color. The allele for Brown body color (B) is dominant to the allele for black body color (b) in the first gene while the allele for Red eye color (R) is dominant to the allele for brown eye color (r) in the second gene.
In a cross between two parents that are heterozygous for the two genes i.e. BbRr × BbRr, each parent will produce the following possible allelic combinations of gametes:
BbRr- BR, Br, bR, and br
Using these gametes in a punnet square (see attached image), 16 possible offsprings will be produced in the ratio 9:3:3:1 where the offsprings and their possible genotypes are;
Brown body and red eyes (B_R_): 9
Brown body and brown eyes (B_rr): 3
Black body and red eyes (bbR_): 3
Black body and brown eyes (bbrr): 1
