.......hope this helps
Can someone please help me
2 answers:
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Answer:
15°
Step-by-step explanation:
Since P is on the median of ΔABC, it is equidistant from points B and C as well as from C and Q. Thus, points B, C, and Q all lie on a circle centered at P. (See the attached diagram.)
The base angles (B and C) of triangle ABC are (180° -30°)/2 = 75°. This means arc QC of the circle centered at P has measure 150°. The diameter of circle P that includes point Q is defined to intersect circle P at R.
Central angle RPC is the difference between arcs QR and QC, so is 180° -150° = 30°. Inscribed angle RQC has half that measure, so is 15°. Angle PQC has the same measure as angle RQC, so is 15°.
Angle PQC is 15°.
Answer:
<em>The base of the triangle = 9inches</em>
Step-by-step explanation:
<u>Explanation</u>:-
The area of the triangle = square units
Given area of the triangle(A) = 54 square inches
Given the height of the triangle (h) = 12 inches
now equating
now simplification, we get
6 b = 54
Dividing '6' on both sides, we get
b = 9
The base of the triangle = 9 inches
<u>Conclusion</u>:-
<em>The base of the triangle = 9 inches</em>