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mafiozo [28]
3 years ago
15

If excess ammonium sulfate reacts with 20.0g of calcium hydroxide how many grams of ammonia are produced

Chemistry
1 answer:
bagirrra123 [75]3 years ago
3 0
The reaction between ammonium sulfate and calcium hydroxide is given below. 
            (NH₄)₂SO₄ + Ca(OH)₂ --> 2NH₃ + CaSO₄ + 2H₂O
From the balance equation, we can conclude that every 74 g of calcium sulfate reacted with enough amount of ammonium sulfate will yield 34 grams of ammonia. From the given amount,
               (20 g calcium sulfate) x (34 grams ammonia / 74 g calcium sulfate)
                               = <em>9.19 g ammonia</em>
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3 0
3 years ago
The formula for binary ionic compound formed between cesium and fluorine
OleMash [197]

Answer:

Cesium fluoride(CsF)

Explanation:

A binary compound is a compound that is composed of 2 distinct element. An ionic compound is composed of ions, usually one is a metal why the other is a non metal. One element gives out electron to form cation and the other receives electron to form anion in a binary compound.

Cesium is a group 1 element and it has one valence electron and it can easily donate this 1 electron to form a bond with other element. Group 1 element are generally very reactive. Cesium is a metal

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When cesium and fluorine bond to form a binary compound cesium donate 1 electron and fluorine receives the 1 electron for both element to form a stable octet. The formula for the binary ionic compound of cesium and fluorine can therefore be expressed as Cesium fluoride(CsF)

7 0
3 years ago
What are five key accomplishments of Marie Curie?
shusha [124]

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Hope this helps :))


5 0
3 years ago
How many moles of boron<br> (B, 10.81 g/mol) are in 37.8<br> grams of boron?<br> [?] moles
madreJ [45]

Answer:

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3 0
2 years ago
How many moles of mgs2o3 are in 193 g of the compound?
Mashutka [201]

Answer:

             1.414 Moles

Solution:

Data Given:

                 Mass of MgS₂O₃  =  193 g

                 M.Mass of MgS₂O₃  =  136.43 g.mol⁻¹

                 Moles  =  ?

Formula Used:

                            Moles  =  Mass ÷ M.Mass

Putting values,

                            Moles  =  193 g ÷ 136.43 g.mol⁻¹

                            Moles =  1.414 mol

8 0
3 years ago
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