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vichka [17]
3 years ago
7

In which scenario is a chemical change occurring?

Chemistry
2 answers:
fenix001 [56]3 years ago
4 0

the answer is A because had this question before

Dimas [21]3 years ago
4 0
Answer is C because each of the above cause a change in state, hence it’s physical, the molecules remain same.
But corrosion is a chemical change, cause there is an addition of water and air to the regular iron molecules
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The highest occupied s and p sublevels are partially filled
natta225 [31]

Answer:

Representative Elements

Explanation:

Representative elements are chemical elements of the long groups of the periodic table identified by the letter A, headed by the elements hydrogen, beryllium, boron, carbon, nitrogen, oxygen, fluorine and helium, as they appear in the periodic table of the elements. .

They are characterized by presenting "external" electronic configurations in their fundamental state ranging from ns1 to ns2np6, unlike the transition elements and internal transition elements.

The representative elements are the elements of groups 1 and 2 (block s), and of groups 13 to 18 (block p) .2 Until a few years ago, these groups were identified with Roman numerals from I to VII with the letter A.3 The elements of group 12 are generally considered as transition metals, however, zinc (Zn), cadmium (Cd), and mercury (Hg) share some properties of both groups, and some scientists believe they should be included as representative elements or elements of the main groups.

Representative elements (with some of the lighter transition metals) are the most abundant elements on earth, in the solar system, and in the universe.

The representative elements are divided into eight groups and are characterized in that their electronic distribution ends in s-p or p-s. The group number results from adding the electrons in the sub-levels s or s and p of the last level.

6 0
3 years ago
If a compound containing only magnesium and oxygen consists of 0.564 g mg and 0.376 g o, what is the compound's empirical formul
jasenka [17]
    the   Empirical  formula    of  the  compound  is  calculated    as  follows

find  the  moles  of  each  element
moles =  mass/molar  mass

that  is Magnesium= 0.564 g /24 g/mol  = 0.0235  moles

For  oxygen    =  0.376 g /16 g/mol=  0.0235  moles
find  the   mole  ratio  by  dividing   both     moles  of  by  0.0235 moles

magnesium =  0.0235/0.0235= 1mole
oxygen=  0.0235 /0.0235= 1mole

therefore  the  empirical    formula  =  MgO
3 0
3 years ago
Which characteristic is true of sexual reproduction but not of asexual reproduction?
Viktor [21]

Answer:

Sexual Reproduction involves two different parties

Explanation:

Asexual is the opposite, so it uses no one else to reproduce

4 0
3 years ago
Read 2 more answers
If 588 grams of FeS2 is allowed to react with 352 grams of O2 according to the following equation, how many grams of Fe2O3 are p
Rainbow [258]

<u>Answer:</u> The mass of iron (III) oxide  produced is 782.5 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For </u>FeS_2<u> :</u>

Given mass of FeS_2 = 588 g

Molar mass of FeS_2 = 120 g/mol

Putting values in equation 1, we get:

\text{Moles of }FeS_2=\frac{588g}{120g/mol}=4.9mol

  • <u>For </u>O_2<u> :</u>

Given mass of O_2 = 352 g

Molar mass of O_2 = 32 g/mol

Putting values in equation 1, we get:

\text{Moles of }O_2=\frac{352g}{32g/mol}=11mol

The chemical equation for the reaction of FeS_2 and oxygen gas follows:

FeS_2+O_2\rightarrow Fe_2O_3+SO_2

By Stoichiometry of the reaction:

1 mole of FeS_2 reacts with 1 mole of oxygen gas

So, 4.9 moles of FeS_2 will react with = \frac{1}{1}\times 4.9=4.9mol of oxygen gas

As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, FeS_2 is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of FeS_2 produces 1 mole of iron (III) oxide

So, 4.9 moles of FeS_2 will produce = \frac{1}{1}\times 4.9=4.9moles of iron (III) oxide

Now, calculating the mass of iron (III) oxide  from equation 1, we get:

Molar mass of iron (III) oxide  = 159.7 g/mol

Moles of iron (III) oxide  = 4.9 moles

Putting values in equation 1, we get:

4.9mol=\frac{\text{Mass of iron (III) oxide}}{159.7g/mol}\\\\\text{Mass of iron (III) oxide}=(4.9mol\times 159.7g/mol)=782.5g

Hence, the mass of iron (III) oxide  produced is 782.5 grams

8 0
3 years ago
Do metals gain or lose electrons as they form ions
Anna71 [15]

Answer:

They usually lose electrons to form ions with 2 positive charges

Explanation:

6 0
3 years ago
Read 2 more answers
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