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Valentin [98]
4 years ago
14

A solution has a (oh-) = 8.6 × 10-5 the poh=, ph=, (h+)=

Chemistry
1 answer:
nalin [4]4 years ago
6 0
POh is calculated by the negative logarithm of hydroxide ions concentration. From the given value, we have:

<span>pOH = -log(8.6 x 10 ^-5)
</span><span>pOH = 4.07
</span><span>
To calculate the pH we use the relation of pOH and pH, expressed as:
</span><span>
14 = pOH + pH
</span><span>pH = 14 - 4.07 = 9.93
</span><span>pH = -log [H+]
</span><span>[H+] = 10^-9.93 = 1.16 x 10^-3 M</span>
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If a solid line represents a covalent bond and a dotted line represents intermolecular attraction, which of these choices shows
blsea [12.9K]
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   Among the choices in the bond (-N...H-O) one side of the Hydrogen is bonded to a highly electronegative atom with a lone pair (-N) and the other side is directly bonded with a highly electronegative atom (O-).

    So -N...H-O- shows a hydrogen bond.</span>
4 0
3 years ago
7. A student has a 25 g sample of gas in a container at STP and adds another 7
BigorU [14]

Answer:

New temperature t2 = [1.28T− 273.15]° C

Explanation:

Given:

Volume v1 = 25 gram

New volume v2 = 25 + 7 = 32 gram

Constant pressure = p

Temperature t1 = T

Find:

New temperature t2

Computation:

Pv1/t1 = Pv2/t2

25 / T = 32 / t2

t2 = 1.28T

New temperature t2 = [1.28T− 273.15]° C

4 0
3 years ago
What does scientific inquiry refer to
Sloan [31]
It refers to the ways scientists explore and study the world based on observations and their works/ evidence.
5 0
3 years ago
The reaction below is at equilibrium. What would happen if more carbon were
schepotkina [342]

Explanation:

C_{(s)} + O_{2(g)} \rightleftharpoons CO_{2(g)}

<em>According to <u>le ch</u></em><em><u>-</u></em><em><u>atelier'</u></em><em><u>s</u></em><em><u> </u></em><em><u>principle</u> when a chemical reaction at equilibrium subjected to any stress, then the equilibrium shifts in that direction in which effect of stress is reduced.</em>

When we would add more number of carbon in above reaction then rate of forward reaction will increase to attain the equilibrium again.

\small \sf \: Thanks \:  for  \: joining  \: brainly \:  community!

5 0
2 years ago
What is the maximum amount in moles of P2O5P2O5 that can theoretically be made from 112 gg of O2O2 and excess phosphorus
Nastasia [14]

Answer:

n_{P_2O_5}^{max}=1.4molP_2O_5

Explanation:

Hello!

In this case, since the reaction between phosphorous and oxygen to form diphosphorous pentoxide is:

2P+\frac{5}{2}O_2\rightarrow P_2O_5

Thus, since phosphorous is in excess and oxygen and diphosphorous pentoxide are in a 5/2:1 mole ratio, we can compute the maximum moles of product as shown below:

n_{P_2O_5}^{max}=112 gO_2*\frac{1molO_2}{32.00gO_2}*\frac{1molP_2O_5}{5/2molO_2}\\\\  n_{P_2O_5}^{max}=1.4molP_2O_5

Best regards!

5 0
3 years ago
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