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3 years ago

A solution has a (oh-) = 8.6 × 10-5 the poh=, ph=, (h+)=

1 answer:

6 0

POh is calculated by the negative logarithm of hydroxide ions concentration. From the given value, we have:

pOH = -log(8.6 x 10 ^-5)
pOH = 4.07

To calculate the pH we use the relation of pOH and pH, expressed as:

14 = pOH + pH
pH = 14 - 4.07 = 9.93
pH = -log [H+]
[H+] = 10^-9.93 = 1.16 x 10^-3 M

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602 hexillion hydrogen atoms is equal to _____ mole of hydrogen atoms.

irina1246 [14]

IT IS EQUAL TO 5 MOLE OF HYDROGEN ATOMS

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2 years ago

Solid lead acetate is slowly added to 75.0 mL of a 0.0492 M sodium sulfate solution. What is the concentration of lead ion requi

Firdavs [7]

Answer:

The concentration of lead ion required to just initiate precipitation is - $2.37\times10^-^5 M$

Explanation:

Lets calculate -:

Solubility equilibrium -: $PbI_2(s)$ ⇄ $Pb^2^+ (aq) + 2I^- (aq)$

Solubility product of $PbI_2$ , $Q=[Pb^2^+]_i_n_i_t_i_a_l$ $[I^-]^2_i_n_i_t_i_a_l$ $=9.8\times10^-^9$

Concentration of $I^-$ $=[KI]=0.0492M$

When the ionic product exceeds the solubility product , precipitation of salt takes place .

$Q_s_p\geq K_s_p$

$[Pb^2^+]_i_n_i_t_i_a_l$ $[I^-]^2_i_n_i_t_i_a_l$ $\geq 9.8\times10^-^9$

$[Pb^2^+]_i_n_i_t_i_a_l$ $[0.0492]^2$ $\geq 9.8\times10^-^9$

$[Pb^2^+]_i_n_i_t_i_a_l$ $\geq \frac{9.8\times10^-^9}{[0.0492]^2}$

$[Pb^2^+]_i_n_i_t_i_a_l$ $\geq$ $\frac{9.8\times10^-^9}{2.42\times10^-^3}$

$[Pb^2^+]_i_n_i_t_i_a_l$ $\geq$ $2.37\times10^-^5 M$

Thus , $PbI_2$ will start precipitating when $[Pb^2^+]_i_n_i_t_i_a_l$ $\geq 2.37\times10^-^5 M$ .

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3 years ago

Does the application of heat to a substance always produce a chemical change?

tatiyna

Answer;

No, sometimes it just causes a physical change, such as ice melting to water.

Explanation;

-The difference between a physical reaction and a chemical reaction is composition. In a chemical reaction, there is a change in the composition of the substances in question; in a physical change there is a difference in the appearance, smell, or simple display of a sample of matter without a change in composition.

Heating a substance may cause a physical change or a chemical change. For example melting ice to water, involves supplying heat to change ice into water which is a chemical change.

-On the other hand, an example of decomposition reactions are chemical reactions which involves supplying heat to a substance; for example decomposing copper (II) nitrate which yields, copper (ii) oxide, nitrogen (iv) oxide and oxygen gas, is chemical reaction.

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3 years ago

What is the mass of 3 moles of chlorine (Cl)

Verizon [17]

Answer:

106.2

Explanation:

Multiply the molar mass by three.

5 0

3 years ago

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