Answer:
- 75.5 g O₂ (g) can be produced from 42.6 g of H₂O (g)
Explanation:
<u>1) Balanced chemical equation (given):</u>
<u>2) Mole ratios:</u>
- 2 moles H₂O(g) : 2 moles H₂(g) : 2 moles O₂(g)
<u>3) Calculate the number of moles of reactant (H₂0):</u>
- number of moles = mass in grams / molar mass
- molar mass of water: 18.015 g/mol
- mass in grams of water: 42.6 g
- number of moles = 42.6 g / 18.05 g/mol = 2.36 moles H₂O
<u>4) Set a proportion using the mole ratio O₂ to H₂O and the actual number of moles of H₂O:</u>
- 2 moles O₂ / 2 moles H₂O = x / 2.36 moles H₂O
<u>5) Convert 2.36 moles O₂ to grams:</u>
- mass in grams = number of moles × molar mass
- mass = 2.36 moles × 32.00 g/mol = 75.5 g O₂
Explanation:
NaCl is a strong salt of strong base and strong acid whereas HCl is a strong acid.
In the solution both dissociates in the solution into their respective ions as shown below:
NaCl ⇒ Na⁺ + Cl⁻
HCl ⇒ H⁺ + Cl⁻
Hence, the ions Na⁺, Cl⁻ and H⁺ are formed and there is no scope of reaction between them for a gas to evolve. They remain in the hydrated state in water.
The question is incomplete, so I tried to find a similar problem online. It is shown in the attached picture. The reaction is
PCl₃ + Cl₂ ⇆ PCl₅
Then, we use the ICE (Initial-Change-Excess) approach as follows:
PCl₃ + Cl₂ ⇆ PCl₅
I 0.5 0.5 0.3
C -x -x +x
E 0.5-x 0.5-x 0.3+x
Total pressure: 0.5 - x + 0.5 - x + 0.3 + x = 1.3
Kp = [PCl₅]/[PCl₃][Cl₂]
0.18 = (0.3+x)/(0.5-x)²
Solving for x,
x= 0.21
Partial pressures would be:
<em>PCl₃ = 0.5 - 0.21 = 0.29 atm</em><em>Cl₂ = 0.5 - 0.21 = 0.29 atm</em><em>PCl₅ = 0.3+0.21 = 0.51 atm</em>
Answer: .45 moles of CO2, H20,and NaCl
Explanation: