Answer:
Take a cupful of water in a beaker and add a few drops of dilute sulphuric acid. Heat the water. When it starts boiling, add copper sulphate powder slowly while stirring continuously. ... Crystals of copper sulphate will be seen at the bottom of the beaker.
Hope it helps
Explanation:
The given data is as follows.
(NaCl) =
(H-O=C-ONO) =
(HCl) =
Conductivity of monobasic acid is
Concentration = 0.01
Therefore, molar conductivity () of monobasic acid is calculated as follows.
=
=
=
Also, =
=
=
Relation between degree of dissociation and molar conductivity is as follows.
=
= 0.1254
Whereas relation between acid dissociation constant and degree of dissociation is as follows.
K =
Putting the values into the above formula we get the following.
K =
=
=
=
Hence, the acid dissociation constant is .
Also, relation between and is as follows.
=
= 3.7454
Therefore, value of is 3.7454.
Humphry Davy First discovered sodium
Ionic bonding is characterized by the combination of two elements, one is a metal while the other one is a nonmetal. Notice the compounds listed. Compounds that are bonded to H are mostly covalent, as well as O3. From the choices, we can tell that the ionic compound are:<em> LiBr</em><span><em> and MgO</em>.</span>
The question is incomplete, here is the complete question:
A chemist prepares a solution of iron (III) bromide by measuring out 2.78 g of iron (III) bromide into a 50. mL volumetric flask and filling the flask to the mark with water.
Calculate the concentration in mmol/L of the chemists iron (III) bromide solution. Be sure your answer has the correct number of significant digits.
<u>Answer:</u> The concentration of iron(III) bromide solution is 0.19 M
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
We are given:
Given mass of iron(III) bromide = 2.78 g
Molar mass of iron(III) bromide = 298.6 g/mol
Volume of solution = 50. mL
Putting values in above equation, we get:
Hence, the concentration of iron(III) bromide solution is 0.19 M