1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
timurjin [86]
3 years ago
12

When heated strongly, copper metal incorporates oxygen to form one of the copper oxides from the last problem. In one experiment

, a crucible weighing 88.00 g was loaded with 10.00 g of copper metal. After 20 minutes of strong heating, the total mass was 100.52 g. How many moles of copper atoms are present in the final product?
Chemistry
1 answer:
Whitepunk [10]3 years ago
8 0

Answer:

1 mol of copper

Explanation:

The mass of the oxide formed is the total mass less the crucible mass, so it is:

100.52 - 88.00 = 12.52 g

It means that 10.00 g is from copper, and 2.52 g is from oxygen. The molar mass of copper is 63.50 g/mol, and the molar mass of oxygen is 16 g/mol. The number of moles (n) is the mass divided by the molar mass:

n Cu = 10.00/63.50 = 0.158 moles

n O = 2.52/16 = 0.158 moles

So, there is the same number of moles of each element, and the product must be: CuO, which has 1 mol of copper.

You might be interested in
what is the inferred pressure, in million of atmospheres, in Earth's interior at a depth of 2900 kilometers?
NemiM [27]

Answer:

1.4 millions atmospheres

Explanation:

8 0
3 years ago
Observation and assessment are most effective when
Artist 52 [7]
I think the answer is A. Hope that helped :)
6 0
3 years ago
How many grams of hydrogen reacts with 32 g of oxygen to produce 34 g of hydrogen peroxide
nordsb [41]

Answer:

2 grams.

Explanation:

H2 + O2 --->  H2O2

Using molar masses:

2*1 g hydrogen   reacts with 2*16  g oxygen.

so 2g H2 reacts with 32 g O2.

8 0
2 years ago
Write the condensed formula from left to right, starting with (CH3)x where x is a number.
pochemuha

Complete question:

Write the condensed formula from left to right, starting with (CH3)x where x is a number.

See attached image for the structure formula of the compound

Answer:

(CH₃)₂CHC(CH₃)₃ named as 2,2,3-Trimethylbutane

Explanation:

If we number the longest chain of the carbon starting from the left, we will observe that there are four carbons in the straight chain as shown in the image.

Starting from first carbon from the left of the carbon chain, at carbon number number 2, there two alkyl group, that is two methyl (CH3 is two). Also at carbon number 3, there are three alkyl group, that is three methyl (CH3 is three).

The condensed formula will be written as;

(CH₃)₂CHC(CH₃)₃

This compound is named as 2,2,3-Trimethylbutane, an isomer of Heptane

3 0
3 years ago
At which temperature will the least amount of time pass before someone detects the odor of a fragrant flower?
alukav5142 [94]
<span>0 °C. 8 °C. 29 °C. 15 °C.</span>
7 0
3 years ago
Other questions:
  • An atom of 105In has a mass of 104.914558 amu. Calculate the binding energy in MeV per NUCLEON. Enter your answer with 3 signifi
    8·1 answer
  • *****
    11·1 answer
  • Which of the following is not a concentration unit (a) 1 molar (b) 1 equivalent (c) 1% by mass (d) 1 molal
    6·1 answer
  • If a substance conducts heat easily, it is considered to be a
    14·2 answers
  • Which statement accurately describes the chemical symbol of an element?
    11·2 answers
  • How many moles are there in 140.g of potassium bromid
    8·1 answer
  • Consider the reaction Mg₂Si(s) + 4 H₂O(ℓ) → 2 Mg(OH)₂(aq) + SiH₄(g). How many grams of silane gas (SiH₄) are formed if 25.0 g of
    6·1 answer
  • What do you think is the primary reason why the Unionid mussel population declined whenever there is a dramatic increase in the
    5·1 answer
  • What is the element name for mg2SiO4
    8·2 answers
  • One way to identify the type of radioactive decay produced in a reaction is to pass the emission through an electric field Descr
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!