Molar volume is when 1 mol of any gas occupies 22.4 L at STP.
Methyl ether has a mass of 8.12 g,
Volume occupied - 3.96 L
If 22.4 L occupied by 1 mol of gas
Then 3.96 L occupied by 1/22.4 x 3.96 = 0.176 mol of gas
The mass of 0.176 mol = 8.12 g
Molar mass is mass of 1 mol
Therefore mass of 1 mol = 8.12/0.176 = 46.1
Molecular weight is 46.1 g/mol
Answer:
V CH3OH = 262.5 mL
Explanation:
- %v/v = (v compound / v sln)×100
∴ %v/v = 21.0 %
∴ v sln = 1.25 L
⇒ v compound = ?
⇒ 21.0 % = ( v compound / 1.25)×100
⇒ 0.21 = v compound / 1.25 L
⇒ (0.21)*(1.25 L) = v compound
⇒ v compound = 0.2625 L = 262.5 mL
<span>F can only have oxidation number of -1
The overall compound has an oxidation number of -1
You have 6 Fs, so 6(-1) = -6
charge from F
X = oxidation number of P
x + (-6) = -1
solve for
x = +5</span>
