Answer:
26.9 g
81%
Explanation:
The equation of the reaction is;
4 KO2(s) + 2 CO2(g) → 3 O2(g) + 2 K2CO3(s)
Number of moles of KO2= 27.9g/71.1 g/mol = 0.39 moles
4 moles of KO2 yields 2 moles of K2CO3
0.39 moles of KO2 yields 0.39 × 2/4 = 0.195 moles of K2CO3
Number of moles of CO2 = 57g/ 44.01 g/mol = 1.295 moles
2 moles of CO2 yields 2 moles of K2CO3
1.295 moles of CO2 yields 1.295 × 2/2 = 1.295 moles of K2CO3
Hence the limiting reactant is KO2
Theoretical yield = 0.195 moles of K2CO3 × 138.205 g/mol = 26.9 g
Percent yield = actual yield/theoretical yield × 100
Percent yield = 21.8/26.9 × 100
Percent yield = 81%
Answer:
Explosion
Explanation:
because The rapid increase in volume and release of energy in an extreme manner is usually generated with high temperature ️and the release of gas
if am correct add me as brightest
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Answer:</h3>
ITS 
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Where n is the number of CARBONS
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A)
By using the General Formula of Alkanes having 4 carbon atoms is
C)
By using the General Formula of Alkanes having 5 carbon atoms is
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IF YOU USE THE SAME FORMULA FOR THE OTHER TWO OPTIONS THE OUTCOME WILL NOT BE AS SAME AS GIVEN IN THE QUESTION SO THOSE TWO ARE CAN NOT BE OUR ANSWER
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HOPE THIS HELPS!</h2>
If the outer shell is filled, the atom is stable. Atoms with unfilled outer shells are unstable, and will usually form chemical bonds with other atoms to achieve stability. Example of an unstable atom with a single electron in its outer-most shell. ... In covalent bonds, atoms share electrons to achieve stability.
Hope this helped!
We first assume that the gas is ideal which is a safe assumption to approximate the answer to the problem. Then we need to know the ideal gas equation and that is:
PV=nRT
where
P- pressure
V- volume
n-number of moles-
R- ideal gas constant
T-temperature.
Since we know that P, T and V are constant, rearranging the equation would lead to:
P/TR = n/V or the ratio of the moles of gas and volume is constant.
(3moles)/2L = (3+x)/4L
where
x is the additional moles.
Solving for x = 3 moles.
