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Hatshy [7]
3 years ago
9

If you run the reaction to make water: 2H2 + O2 → 2H2O, starting with 3.0 moles of hydrogen gas and 2.0 moles of oxygen gas, wha

t is the theoretical yield of your reaction (in grams)?
Chemistry
2 answers:
Alex_Xolod [135]3 years ago
7 0

Answer:

54 g is the theoretical yield

Explanation:

This is the reaction:

2H₂ + O₂ → 2H₂O

So 2 moles of hydrogen react with 1 mol of oxygen, to produce 2 mol of water.

If I have 3 moles of H₂ and 2 moles of O₂, the my limiting reactant is the hydrogen.

1 mol of O₂ react with 2 moles of H₂

S 2 mol of O₂ would react with 4 moles (I only have 3 moles)

Then, ratio is 2:2 the same as 1:1

As 2 mol of H₂ produce 2 moles of water, 3 moles of H₂ will produce 3 moles of H₂O.

This is the theoretical yield in moles. Let's convert them to mass (mol . molar mass)

3 mol . 18g/m = 54 g

konstantin123 [22]3 years ago
3 0

Answer:

The theoretical yield of the reaction is 54.06 grams

Explanation:

Step 1: Data given

Moles of hydrogen gas = 3.0 moles

Moles of oxygen gas = 2.0 mol

Molar mass of H2O = 18.02 g/mol

Step 2: The balanced equation

2H2 + O2 → 2H2O

Step 3: Calculate the limiting reactant

For 2 moles H2 consumed, we need 1 mol O2 to produce 2 moles of H2O

Hydrogen gas is the limiting reactant. It will be completely consumed. (3.0 moles).

Oxygen gas is in excess. There will react 3.0/2 = 1.5 moles of O2.

There will remain 2.0 -1.5 = 0.5 moles

Step 4: Calculate the moles of H2O

For 2 moles of H2 we'll have 2 moles of H2O

For 3 moles H2 we'll have 3.0 moles of H2O

Step 5: Calculate theoretical yield of H2O

Mass H2O = moles H2O * molar mass H2O

Mass H2O = 3.0 moles * 18.02 g/mol

Mass H2O = 54.06 grams

The theoretical yield of the reaction is 54.06 grams

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A wooden block has a mass of 20 g and dimensions of 5 cm x 1 cm x 1 cm.
marta [7]

Answer:

V = 5 cm³

ρ = 4 g/cm³

Explanation:

Step 1: Calculate the volume (V)

We have a wooden cuboid of dimensions 5 cm × 1 cm × 1 cm. We can calculate its volume using the following expression.

V = 5 cm × 1 cm × 1 cm

V = 5 cm³

Step 2: Calculate the density (ρ)

The density is equal to the mass divided by the volume.

ρ = m / V

ρ = 20 g / 5 cm³

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4 0
3 years ago
Two gases X and Y are found in the atmosphere in only trace amounts because they decompose quickly. When exposed to ultraviolet
igomit [66]

Answer:

1. Yes

2. After 68.1 mins, pX < pY.

Explanation:

Assuming the total gas pressure is 1 atm, let the partial pressure of Y be y, partial pressure of X will be 0.25y + y = 1.25y

1.25y + y = 1atm

2.25y = 1 atm

y = 1 atm / 2.25 = 0.44 atm

Then partial pressure of X = 0.56 atm

The partial pressure of a gas in a mixture of gases is directly proportional to the mole fraction of the gas.

Therefore the mole fraction of X and Y is 0.56 and 0.44 respectively.

The partial pressures of X and Y becomes half of their original values at 1.25 h = 85 min and Y at 150 min respectively.

The partial pressure after some time can be calculated from the half-life equation :

m = m⁰ *  1/2ⁿ

Where m = the remaining mass, m⁰ = initial mass, and n is number of half-lives undergone.

Let partial pressures represent the mass, and n for X and Y be a and b respectively:

pX  = 0.56/2ᵃ

pY = 0.44/2ᵇ

We then determine when Partial pressure of X, pX = Partial pressure of Y, pY

0.56/2ᵃ = 0.44/2ᵇ

2ᵃ/2ᵇ = 0.56/0.44

2ᵃ/2ᵇ = 1.27

2ᵃ⁻ᵇ = 2⁰°³⁴⁵

a - b = 0.345

Let this time be t, therefore,

For X; t = 85a and For Y: t = 150b

85a = 150b

then, a = 1.76b

1.76b - b = 0.345

0.760b = 0.345

b = 0.454 and,

a = 0.345 + 0.454 = 0.799

So,  X goes through 0.779 half-lives while Y goes through 0.454 half-lives Then, the time for both X and Y to have the same amount is:

t = 150 * 0.454 = 68.1 min

After 68.1 mins, pX < pY.

5 0
3 years ago
Is -280 f degrees hot or cold
N76 [4]

Answer:

COLD

Explanation:

6 0
3 years ago
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