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Hatshy [7]
3 years ago
9

If you run the reaction to make water: 2H2 + O2 → 2H2O, starting with 3.0 moles of hydrogen gas and 2.0 moles of oxygen gas, wha

t is the theoretical yield of your reaction (in grams)?
Chemistry
2 answers:
Alex_Xolod [135]3 years ago
7 0

Answer:

54 g is the theoretical yield

Explanation:

This is the reaction:

2H₂ + O₂ → 2H₂O

So 2 moles of hydrogen react with 1 mol of oxygen, to produce 2 mol of water.

If I have 3 moles of H₂ and 2 moles of O₂, the my limiting reactant is the hydrogen.

1 mol of O₂ react with 2 moles of H₂

S 2 mol of O₂ would react with 4 moles (I only have 3 moles)

Then, ratio is 2:2 the same as 1:1

As 2 mol of H₂ produce 2 moles of water, 3 moles of H₂ will produce 3 moles of H₂O.

This is the theoretical yield in moles. Let's convert them to mass (mol . molar mass)

3 mol . 18g/m = 54 g

konstantin123 [22]3 years ago
3 0

Answer:

The theoretical yield of the reaction is 54.06 grams

Explanation:

Step 1: Data given

Moles of hydrogen gas = 3.0 moles

Moles of oxygen gas = 2.0 mol

Molar mass of H2O = 18.02 g/mol

Step 2: The balanced equation

2H2 + O2 → 2H2O

Step 3: Calculate the limiting reactant

For 2 moles H2 consumed, we need 1 mol O2 to produce 2 moles of H2O

Hydrogen gas is the limiting reactant. It will be completely consumed. (3.0 moles).

Oxygen gas is in excess. There will react 3.0/2 = 1.5 moles of O2.

There will remain 2.0 -1.5 = 0.5 moles

Step 4: Calculate the moles of H2O

For 2 moles of H2 we'll have 2 moles of H2O

For 3 moles H2 we'll have 3.0 moles of H2O

Step 5: Calculate theoretical yield of H2O

Mass H2O = moles H2O * molar mass H2O

Mass H2O = 3.0 moles * 18.02 g/mol

Mass H2O = 54.06 grams

The theoretical yield of the reaction is 54.06 grams

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1 year ago
Tính [H] và [OH] của dung dịch HC1 0,1M? Tính pH của dung dịch?
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Answer:

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Explanation:

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3 0
3 years ago
Consider the reaction given below.
Drupady [299]

Answer:

  • <u>K =  0.167 s⁻¹</u>

Explanation:

<u>1) Rate law, at a given temperature:</u>

  • Since all the data are obtained at the same temperature, the equilibrium constant is the same.

  • Since only reactants A and B participate in the reaction, you assume that the form of the rate law is:

        r = K [A]ᵃ [B]ᵇ

<u>2) Use the data from the table</u>

  • Since the first and second set of data have the same concentration of the reactant A, you can use them to find the exponent b:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₂ = (1.50)ᵃ (2.50)ᵇ = 2.50 × 10⁻¹ M/s

         Divide r₂ by r₁:     [ 2.50 / 1.50] ᵇ = 1 ⇒ b = 0

  • Use the first and second set of data to find the exponent a:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₃ = (3.00)ᵃ (1.50)ᵇ = 5.00 × 10⁻¹ M/s

        Divide r₃ by r₂: [3.00 / 1.50]ᵃ = [5.00 / 2.50]

                                  2ᵃ = 2 ⇒ a = 1

         

<u>3) Write the rate law</u>

  • r = K [A]¹ [B]⁰ = K[A]

This means, that the rate is independent of reactant B and is of first order respect reactant A.

<u>4) Use any set of data to find K</u>

With the first set of data

  • r = K (1.50 M) = 2.50 × 10⁻¹ M/s ⇒ K = 0.250 M/s / 1.50 M = 0.167 s⁻¹

Result: the rate constant is K =  0.167 s⁻¹

6 0
3 years ago
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tino4ka555 [31]

Answer:

False

Explanation:

7 0
3 years ago
Read 2 more answers
Mercury can be obtained by reacting mercury(I) sulfide with calcium oxide. How many grams of calcium oxide are needed to produce
OLga [1]
First, 55 g of Hg is 3.65 moles because one mole of Hg has a molar mass of 200.59

Then, the mole ratio of Hg to CaO is 8:4 or 2:1. SO we divide 3.65 by 2 to get 1.82 moles of CaO

This is the same as 102.06 grams because one mole of CaO has a molar mass of 56.0774

Hope this helps!
4 0
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