The half-life of polonium-210, given that it decays from 98.3 micrograms to 12.3 micrograms in 414 days is 138 days
<h3>How to determine the number of half-lives </h3>
- Original amount (N₀) = 98.3 micrograms
- Amount remaining (N) = 12.3 micrograms
- Number of half-lives (n) =?
2ⁿ = N₀ / N
2ⁿ = 98.3 / 12.3
2ⁿ = 8
2ⁿ = 2³
n = 3
<h3>How to determine the half life </h3>
- Number of half-lives (n) = 3
- Time (t) = 414 days
- Half-life (t½) = ?
t½ = t / n
t½ = 414 / 3
t½ = 138 days
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neutrons to the carbon-12 and carbon-14
Answer:
http://hyperphysics.phy-astr.gsu.edu/hbase/Biology/imgbio/treecycle.p ng
Explanation:
Answer:
![Ka=\frac{[H^+][HCOO^-]}{[HCOOH]}](https://tex.z-dn.net/?f=Ka%3D%5Cfrac%7B%5BH%5E%2B%5D%5BHCOO%5E-%5D%7D%7B%5BHCOOH%5D%7D)
Explanation:
Hello,
In this case, the weak ionization reaction for formic acid is:
In such a way, we simply recall the law of mass action in order to represent the weak ionization constant, Ka, for such process, by taking into account that the concentration of products is divided over the concentration of reactants as shown below:
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The new pressure of the gas would be 505.58 torr
<h3>Boyle's law</h3>
According to Boyle's law, the pressure of a gas is inversely proportional to its volume, provided that the temperature is constant.
This can be mathematically represented as: P1V1 = P2V2
In this case, P1 = 759.4 torr, P2 is what we are looking for, V1 = 97.6 mL, and V2 = 146.6 mL
Hence, P2 = P1V1/V2 = 759.4x97.6/146.6 = 505.58 torr
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