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3 years ago

A sound level of 96 dB is how many times as intense as one of 90 dB?

Physics

1 answer:

Katyanochek1 [597]3 years ago

4 0

Answer:

A sound level of 96 dB is 4 times as intense as one of 90 dB

Explanation:

The formula of the intensity level of sound in decibels is given as follows:

Intensity Level = 10 log₁₀(I/I₀)

where,

I = Intensity of Sound

I₀ = Reference Intensity Level = 10⁻¹² W/m²

Therefore, for 96 dB sound level:

96 = 10 log₁₀(I₁/10⁻¹²)

log₁₀(I₁/10⁻¹²) = 96/10

I₁/10⁻¹² = 10^9.6

I₁ = (10⁻¹²)(4 x 10⁹)

I₁ = 0.004 W/m²

For 90 dB sound level:

90 = 10 log₁₀(I₂/10⁻¹²)

log₁₀(I₂/10⁻¹²) = 90/10

I₂/10⁻¹² = 10^9

I₂ = (10⁻¹²)(10⁹)

I₂ = 0.001 W/m²

Therefore,

I₁/I₂ = 0.004/0.001

I₁ = 4 I₂

Hence, the sound level of 96 dB is 4 times as intense as one of 90 dB.

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1. After being struck by a bowling ball, a 1.5 kg bowling pin moving to the right at +3.0 m/s collides with

salantis [7]

Answer:

a) Final velocity of second bowling pin is 2.5m/s.

b) Final velocity of second bowling pin is 3 m/s.

Explanation:

Let 'm' be the mass of both the bowling pin -

m = 1.5 kg

Initial velocity of first bowling pin -

$v_{1} = 3 m/s$

In any type of collision between two bodies in horizontal plane , momentum is conserved along the line of impact.

a) Since , initial velocity of second bowling pin is 0 m/s -

Initial momentum ,

$p_{1} = mv_{1}$

Final velocity of first bowling pin , $v_{2} = 0.5m/s$ [Considering initial direction of motion of the first bowling pin to be positive]

Let $u_{2}$ be the final velocity of the second bowling pin.

∴ Final momentum ,

$p_{2} = mv_{2} + mu_{2}$ .

Now ,

$p_{1} = p_{2}$

∴ $mv_{1} = mv_{2} + mu_{2}$

∴ $u_{2}$ = 3 - 0.5 = 2.5 m/s

∴ Final velocity of second bowling pin is 2.5 m/s.

b) Since , initial velocity of second bowling pin is 0 m/s -

Initial momentum ,

$p_{1} = mv_{1}$

Final velocity of first bowling pin , $v_{2} = 0m/s$ [given][Considering initial direction of motion of the first bowling pin to be positive]

Let $u_{2}$ be the final velocity of the second bowling pin.

∴ Final momentum ,

$p_{2} = mv_{2} + mu_{2}$ .

Now ,

$p_{1} = p_{2}$

∴ $mv_{1} = mv_{2} + mu_{2}$

∴ $u_{2}$ = 3 - 0 = 3 m/s

∴ Final velocity of second bowling pin is 3 m/s.

7 0

3 years ago

Se colocan tres objetos, muy cerca uno del otro, dos al mismo tiempo. Cuando se juntan los objetos A y B, se repelen. Cuando se

docker41 [41]

Answer:

Los objetos A y C tienen cargas del mismo signo (opcion a)

Explanation:

Hay dos tipos de cargas : cargas positivas y cargas negativas.

La Ley de Coulomb dice que la fuerza electrostática entre dos cargas puntuales es proporcional al producto de las cargas e inversamente proporcional al cuadrado de la distancia que las separa, y tiene la dirección de la línea que las une y se cumple que:

La fuerza ejercida sobre una carga apunta hacia la otra cuando las dos tienen distinto signo (fuerza atractiva).
El sentido de la fuerza se dirige hacia el lado opuesto de la carga cuando ambas tienen el mismo signo (fuerza repulsiva).

Es decir que las cargas de igual signo se repelen, mientras que las de diferente signo se atraen.

Entonces, si se juntan los objetos A y B y se repelen significa que la carga es del mismo signo.

Cuando se acercan los objetos B y C, se repelen. Entonces significa que posee carga de igual signo.

Por lo que podes concluir que los objetos A y C tienen cargas del mismo signo (opcion a)

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3 years ago

What is the momentum of a 800 kg car traveling at 20 m/s

BabaBlast [244]

Answer: The momentum of the car is 16000 kg.m/s

Explanation:

Momentum is defined as the force that keeps the object moving. It is also defined as the product of mass and velocity of an object.

Mathematically,

$p=m\times v$

where,

p = momentum of the car = ?

m = mass of the car = 800 kg

v = velocity of the car = 20 m/s

Putting values in above equation, we get:

$p=800kg\times 20m/s\\\\p=16000kg.m/s$

Hence, the momentum of the car is 16000 kg.m/s

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3 years ago

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xenn [34]

Answer:

Explanation:

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3 years ago

An element has a charge of -3, has 8 protons, 11 neutrons, and electrons

Sati [7]

Question isn’t clear
If it’s asking the no of electrons then -
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3 years ago