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3 years ago

Need help answering this question for #30

Physics

2 answers:

frozen [14]3 years ago

8 0

Add all your numbers up and that would be your answer

dezoksy [38]3 years ago

6 0

I think u would add them all up and then write down your answers

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How does respiratory and nervous interconnected I will make brainlest!!

stiv31 [10]

The medulla in the brain controls the breathing rate in the lungs

4 0

3 years ago

Two trains, each having a speed of 28 km/h, are headed at each other on the same straight track. A bird that can fly 60 km/h fli

Semenov [28]

Answer:

The value is $D = 70.71 \ km$

Explanation:

From the question we are told that

The speed of each train is $v = 28 \ km/h$

The speed of the bird is $v_1 = 60 \ km/h$

The distance between the trains is $d = 66 \ km$

Generally the time taken before the collision occurs is mathematically represented as

$t = \frac{d}{2 * v}$

=> $t = \frac{66 }{2 * 28}$

=> $t = 1.18 \ h$

The total distance covered by the bird is mathematically represented as

$D = v_1 * t$

=> $D = 60 * 1.18$

=> $D = 70.71 \ km$

7 0

3 years ago

Please help with these i dont know how to do them

Svetradugi [14.3K]

20.0M/S. IS THE HORIZONTAL VELOCITY OF THE BALL JUST BEFORE IT REACHES THE GROUND

12.2 SECONDS IS THE APPROXIMATE TOTAL TIME REQUIRED FOR THE BALL

3 0

4 years ago

A street light is on top of a 9 foot pole. Joe, who is 3 feet tall, walks away from the pole at a rate of 4 feet per second. At

Gekata [30.6K]

Answer:2 ft/s

Explanation:

Given

Length of Pole is 9 ft

Length of Joe is 3 ft

Joe walks away from Pole at the rate 4 ft/s

Let Joe is x m away from Pole so its shadow length is x'

From Similar triangle concept

$\frac{x'}{x+x'}=\frac{3}{9}$

3x'=x+x'

x=2x'

and it is given $\frac{\mathrm{d} x}{\mathrm{d} t}=4 ft/s$

Differentiating

$\frac{\mathrm{d} x}{\mathrm{d} t}=2\frac{\mathrm{d} x'}{\mathrm{d} t}$

$4=2\times \frac{\mathrm{d} x'}{\mathrm{d} t}$

$\frac{\mathrm{d} x'}{\mathrm{d} t}=2 ft/s$

6 0

3 years ago

A helium-neon laser (λ = 633 nm) illuminates a single slit and is observed on a screen 1.50 m behind the slit. The distance betw

mario62 [17]

Answer:

$0.2$ mm

Explanation:

As we know that

$Y = \frac{m\lambda * D}{d}$

where

m represents the order of minimum

y represents the distance on the screen of the minimum from central axis

λ is the wavelength of the light

D is the distance between screen-to-slit

d represents the width of the slit

For first minima

$y_1 = \frac{1 * 633 * 10^{-9}*1.5}{d}$

For second minima

$y_2 = \frac{2 * 633 * 10^{-9}*1.5}{d}$

$Y_2 - Y_1 = 0.00475m\\\frac{633 * 10^{-9} * 1.5 }{d} = 0.00475\\d = 0.0002 m\\d = 0.2 mm$

3 0

3 years ago