Answer:
Explanation:
velocity of wave in a tense wire is given by the expression
v is velocity . T is tension and m is mass per unit length .
for steel wire
m = π r² ρ where r is radius and ρ is density
= 3.14 x (5.3 x 10⁻⁴)²x7.75 x 10³
= 683.57 x 10⁻⁵ kg/m
v = 
= 1.47 x 10² m /s
= 147 m /s
for iron wire
m = π r² ρ where r is radius and ρ is density
= 3.14 x (5.3 x 10⁻⁴)²x7.86 x 10³
= 693.27 x 10⁻⁵ kg/m
= 146 m /s
Time taken to move from one end to another
= 17.7 / 147 + 28.5 / 146
= .12 + .195
= .315 s .
Answer:
b 1000
if you multiply 2m/s by 500 you get 1000 it should look like this.
500 x 2m/s
Answer:
Ttop = T1 + T2
Explanation:
The three tension forces act on the pulley. With the assumption that the pulley has a negligible mass, the force of gravity on it is zero. So only forces Ttop, T1 and T2 act on the pulley.
The tension force Ttop acts upwards on the pulley while the tension forces T1 and T2 act on the pulley downwards. The pulley is in equilibrium so the sum of upward forces acting on the pulley and the sum of downward forces acting on the pulley must be equal.
So
Ttop = T1 + T2.
