Answer:
a) The work done on the particle has a positive sign.
Explanation:
When a positive charge is placed in a electric field , a force is exerted by electric field along the direction of the electric field . But the external force is acting on it so that displacement is opposite to the field . That means the external force is acting opposite to electric force on the charged particle.
The displacement is along the external force applied so both force and displacement are positive . Hence work done is positive .
Work done by electric field is negative , because displacement and electric force are opposite.
Given Information:
Mass = m = 500 kg
Acceleration = a = 10 cm/s²
Required Information:
Magnitude of rightward net force = F = ?
Answer:
Magnitude of rightward net force = 50 N
Explanation:
From the Newton's second law of motion
F = ma
Where m is the mass and a is the acceleration
To get force in Newtons first convert 10 cm/s² into m/s²
10/100 = 0.1 m/s²
F = 500*0.1
F = 50 N
Therefore, the magnitude of rightward net force acting on it is 50 Newtons.
The magnetic force experienced by the proton is given by

where q is the proton charge, v its velocity, B the magnitude of the magnetic field and

the angle between the direction of v and B. Since the proton moves perpendicularly to the magnetic field, this angle is 90 degrees, so

and we can ignore it in the formula.
For Netwon's second law, the force is also equal to the proton mass times its acceleration:

So we have

from which we can find the magnitude of the field: