Answer:
2354.4 Pa
40221 Pa
Explanation:
= Density = 1000 kg/m³
g = Acceleration due to gravity = 9.81 m/s²
h = Depth
The pressure difference would be
The pressure difference in the first case is 2354.4 Pa
The pressure difference in the second case is 40221 Pa
Answer:
A) T = 95.12 N, B) L_man - 0.59 L
Explanation:
A) For this problem we must use the equilibrium, translational and rotational equations
∑τ = 0
Let's fix our reference system at the top of the stairs, the anti-clockwise rotation is positive
W x/2 + W_man x_man - T y = 0 (1)
Let's look with trigonometry for distances
cos 52 = x / L
x = L cos 52
sin 52 = y / L
y = L sin52
The man indicates it is at L / 3, so its distance is
x_man = L/3 cos 52
We replace
W L/2 cos 52 + W_man L/3 cos 52 - T L sin 52 = 0
T = cos 52 (W / 2 + W_man / 3) / sin 52
T = cos 52 (137/2 + 16.3 9.8 / 3) / sin 52
T = 121.75 ctan 52
T = 95.12 N
B) let's look for the maximum distance (x) that can be before breaking the rope
L_man = (-W L / 2 cos 52 + T L sin 52) / W_man cos 52
L_man / L = (-W / 2 ctan 52 + T tan 52) / W_man
L_man / L = ( -137/2 ctan 52 + 116 tan 52) / (16.3 9.8)
L_man / L = (-53.518 +148.47) /159.74
L_ma / L = 0.594
The man then climb a length of 0,59 (59%) along the length of the stairs
D. Screw is the answer to your question
The time it takes for a point to reach 0 displacement from maximum displacement is
of a cycle. Thus, one period (
) will take
.
The frequency is simply
.
The speed is given by:
Answer:
5.3 × 10^(-8) m
Explanation:
We are given;
Shear force; F = 400 N
Length of cube; L_o = 30 cm = 0.3 m
Shear modulus; S = 2.5 × 10^(10) N/m²
Now,the resulting relative displacement can be gotten from the formula;
F = A × S × Δx/L_o
Where Δx is resulting relative displacement
A is area.
Area of cube = (L_o)² = 0.3² = 0.09
Thus, making Δx the subject, we have;
Δx = (F × L_o)/(A × S)
Plugging in the relevant values;
Δx = (400 × 0.3)/(0.09 × 2.5 × 10^(10))
Δx = 5.3 × 10^(-8) m