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adelina 88 [10]
3 years ago
9

A spaceship is travelling at 20,000.0 m/s. After 5.0 seconds, the rocket thrusters are turned on. At the 55.0 second mark, the s

hip has a velocity of 24,000.0 m/s. What is the acceleration of the rocket?
Physics
1 answer:
tankabanditka [31]3 years ago
7 0

Answer:

80 m/s^2

Explanation:

The acceleration of an object is given by:

a=\frac{v-u}{t}

where

v is the final velocity

u is the initial velocity

t is the time interval it takes for the velocity to change from u to v

For the rocket in this problem,

u = 20,000 m/s

v = 24,000 m/s

t = 55.0 - 5.0 = 50.0 s

Substituting,

a=\frac{24000-20000}{50}=80 m/s^2

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A searchlight is 210 ft from a straight wall. As the beam moves along the​ wall, the angle between the beam and the perpendicula
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Answer:

The length of the beam increasing is 9.64 ft/s.

Explanation:

Given that,

Height = 210 ft

Distance =290 ft

According to figure,

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\cos\theta=\dfrac{210}{x}....(I)

Put the value of x in the equation

\cos\theta=\dfrac{210}{290}

\cos\theta=\dfrac{21}{29}=0.72

Now, \sin\theta=\dfrac{20}{29}

On differentiate of equation (I)

-\sin\theta\dfrac{d\theta}{dt}=-\dfrac{-210}{x^2}\dfrac{dx}{dt}

\sin\theta=\dfrac{210}{x^2}\dfrac{dx}{dt}

Put the value in the equation

\sin\dfrac{20}{29}\times2.0=\dfrac{210}{(290)^2}\dfrac{dx}{dt}

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Hence, The length of the beam increasing is 9.64 ft/s.

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3 years ago
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vovikov84 [41]

Answer:

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Explanation:

From the question given above, the following data were obtained:

Height (h) of cliff = 2.8 m

Initial velocity (u) = 0 m/s

Final velocity (v) =?

NOTE: Acceleration due to gravity (g) = 9.8 m/s²

Finally, we shall determine how fast (i.e final velocity) Tarzan will be moving at the bottom. This can be obtained as follow:

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