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USPshnik [31]
1 year ago
12

A 1,350 kg package is dropped from a plane from a height of 760meters. What is its potential energy right before it starts to fa

ll?
Physics
1 answer:
larisa [96]1 year ago
7 0

Given:

Mass (m) of package = 1350 kg

Height, h = 760 meters

Let's find the potential energy right before the object starts to fall

To find the potential energy, apply the formula below:

P.E=m\ast g\ast h

Where:

m = 1350 kg

h = 760 meters

g is the acceleration due to gravity = 9.8 m/s^2

Substitute values into the equation:

\begin{gathered} PE=1350\ast9.8\ast760 \\  \\ PE=10054800\text{ J }\approx10.0548\text{ MJ} \end{gathered}

Therefore, the potential energy right before the object starts of fall is 10.0548 megajoules.

ANSWER:

10.0548 MJ

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Some cities now implement signal lights designed to specifically apply to _____ rather than motorized vehicles.
dmitriy555 [2]

The correct answer is C; Bicycles.

Further Explanation:

In major cities, in the United States, have implemented signal lights specifically designed for bicycle riders. The riders also have their own designated bike lanes in many large cities. Drivers in vehicles, are to give the right of way to people on bicycles.

Bicycle riders are to follow the same laws and laws specifically for the riders or they can face fines and tickets.

Learn more about bicycle laws at brainly.com/question/8934107

#LearnwithBrainly

7 0
2 years ago
PLEASE ANYONE SOLVE THIS NOW FAST PLEASE IM IN A HURRY
m_a_m_a [10]

Hello,

<u>Solution for A:</u>

Force = 3.00N

Mass = 0.50 Kgs

Time = 1.50 Seconds

According to newton's second law of motion;

Force = Mass times Acceleration(a)

3.00 = 0.50 * a

a = 3.00/0.50 = 6.00 m/s^2

We know that acceleration = Velocity / time

So Velocity = time * acceleration = 1.50 * 6 = 9.00 m/s^2

<u>Solution for B:</u>

The net force = 4.00N - 3.00N = 1.00N to the left

Force = 1.00N

Mass = 0.50Kg

Time = 3.00 Seconds

Again; F = MA (Where F is force, M is mass and A is acceleration)

1.00N = 0.5 * A

A = 1/0.5 = 2 m/s^2

Velocity = Acceleration * Time = 2 * 3 = 6 m/s

3 0
3 years ago
A train at rest emits a sound at a frequency of 1057 Hz. An observer in a car travels away from the sound source at a speed of 2
il63 [147K]

Answer:

993.52 Hz

Explanation:

The frequency of sound emitted by the stationery train is 1057 Hz.

The car travels away from the train at 20.6 m/s.

The frequency the observer hears is given by the formula:

f_o = \frac{v - v_o}{v}f

where v = velocity of sound = 343 m/s

vo = velocity of observer

f = frequency from source

This phenomenon is known as Doppler's effect.

Therefore:

f_o = \frac{343 - 20.6}{343} * 1057\\ \\f_o = 322.4 / 343 * 1057\\\\f_o = 993.52 Hz

The frequency heard by the observer is 993.52 Hz.

4 0
3 years ago
What does the speedometer of a car tell you?
Gelneren [198K]

Answer:

Speedometer, instrument that indicates the speed of a vehicle, usually combined with a device known as an odometer that records the distance traveled.

Explanation:

5 0
2 years ago
Consider the situation||: A child pulls a sled by a rope across the lawn at a constant speed. Of the forces listed, identify whi
Mice21 [21]

Answer:

Gravitational

Tension

Normal

Friction.

Explanation:

The forces acting on the sled are:

Tension: the tension from the rope, this is the force that "moves" the sled.

Friction: kinetic friction between the sled and the ground as the sled moves.

There are another two forces that also act on the sled, but that "has no effect"

Gravitational force: This force pulls the sled down, against the floor.

Normal force: This force "opposes" to the gravitational one, so they cancel each other.

These two forces cancel each other, so they have no direct impact on the movement of the sled. BUT, the friction force depends on the weight of the moving object, and the weight of the moving object depends on the gravitational force, so we need gravitational force in order to have friction force.

Then we can conclude that the forces acting on the sled are:

Gravitational

Tension

Normal

Friction.

6 0
2 years ago
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