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USPshnik [31]
1 year ago
12

A 1,350 kg package is dropped from a plane from a height of 760meters. What is its potential energy right before it starts to fa

ll?
Physics
1 answer:
larisa [96]1 year ago
7 0

Given:

Mass (m) of package = 1350 kg

Height, h = 760 meters

Let's find the potential energy right before the object starts to fall

To find the potential energy, apply the formula below:

P.E=m\ast g\ast h

Where:

m = 1350 kg

h = 760 meters

g is the acceleration due to gravity = 9.8 m/s^2

Substitute values into the equation:

\begin{gathered} PE=1350\ast9.8\ast760 \\  \\ PE=10054800\text{ J }\approx10.0548\text{ MJ} \end{gathered}

Therefore, the potential energy right before the object starts of fall is 10.0548 megajoules.

ANSWER:

10.0548 MJ

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4 0
3 years ago
A large crane consists of a 20 m, 3,000 kg arm that extends horizontally on top of a vertical tower. The arm extends 15 m toward
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Answer:

m=18000kg

Explanation:

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Generally the equation for Torque Balance is mathematically given by

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7 0
3 years ago
Con lắc lò xo có độ cứng k = 100N/m được gắn vật có khối lượng m=0.1kg, kéo vật ra khỏi vị trí cân bằng 1 đoạn 5cm rồi buông tay
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Answer:

The maximum velocity is 1.58 m/s.

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A spring pendulum with stiffness k = 100N/m is attached to an object of mass m = 0.1kg, pulls the object out of the equilibrium position by a distance of 5cm, and then lets go of the hand for the oscillating object. Calculate the achievable vmax.

Spring constant, K = 100 N/m

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3 years ago
A student pushes on a 20.0 kg box with a force of 50 N at an angle of 30° below the horizontal. The box accelerates at a rate of
PtichkaEL [24]

Answer:

225 N

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"Below the horizontal" means he's pushing down at an angle.

Draw a free body diagram of the box.  There are three forces: normal force N pushing up, weight force mg pulling down, and the applied force F at an angle θ.

Sum of forces in the y direction:

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N = F sin θ + mg

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When there was know life on the earth
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