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3 years ago

A rightward force of 4.0 N is exerted upon an object for a distance of 3.0 meters.

Physics

1 answer:

julia-pushkina [17]3 years ago

8 0

Answer:

W = 12 J

Explanation:

Given that,

Force, F = 4 N

The object moves in rightward direction for a distance of 3 m.

Work done on the object is given by :

$W=F\times d\\\\=4\ N\times 3\ m\\\\=12\ J$

So, the work done on the object is 12 J.

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An object is released from rest and falls in free fall motion. The speed v of the object after it has fallen a distance y is giv

konstantin123 [22]

Answer:

8.91 %

Explanation:

Since v² = 2gy

By the relative error formula,

2Δv/v = Δg/g + Δy/y multiplying by 100%, we have

2Δv/v × 100% = Δg/g × 100 % + Δy/y × 100%

2(Δv/v × 100%) = Δg/g × 100 % + Δy/y × 100%

Δg/g × 100 % = 2(Δv/v × 100%) - Δy/y × 100%

Since Δv/v × 100% = 3.69 % and Δy/y × 100% = 5 %

Since we have a difference for the percentage error in g, we square the percentage errors and add them together. So,

[Δg/g × 100 %]² = [2(Δv/v × 100%)]² + [Δy/y × 100%]²

[Δg/g × 100 %]² = [2(3.69)]² + [5%]²

[Δg/g × 100 %]² = [4)(3.69 %)² + [5%]²

[Δg/g × 100 %]² = 54.4644 %² + 25%²

[Δg/g × 100 %]² = 79.4644 %²

taking square-root of both sides, we have

[Δg/g × 100 %] = 8.91 %

So, the percent uncertainty in the calculated value of g is 8.91 %

6 0

3 years ago

What is liquidity preferences?

ZanzabumX [31]

<h3>In macroeconomic theory,liquidity preference is the demand for money, considered as liquidity.</h3>

5 0

3 years ago

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An airplane cabin is pressurized to 570 mmhg. what is the pressure inside the cabin in atmospheres?

abruzzese [7]

1 atm corresponds to 760 mmHg, so we can set up a simple proportion to find how many atmospheres correspond to 570 mmHg:
$1 atm: 760 mmHg = x: 570 mmHg$
and from this, we find
$x= \frac{1 atm \cdot 570 mmHg}{760 mmHg} =0.75 atm$

8 0

3 years ago

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Which stimulant drug leads to a brief 15 to 30 minute rush of euphoria and energy followed by a crash and immediate craving for

solmaris [256]

Answer:

ketamine.

Explanation:

yoda told me.

8 0

3 years ago

malfutka [58]

Answer:

<em>The penny will hit the ground at 6.39 seconds</em>

Explanation:

The penny is dropped from a height of y=200 m. The equation of the height on a free-fall motion is given by:

$\displaystyle y=\frac{gt^2}{2}$

Where $g=9.8\ m/s^2$ , and t is the time.

Solving for t:

$\displaystyle t=\sqrt{\frac{2y}{g}}$

Using the value y=200:

$\displaystyle t=\sqrt{\frac{2*200}{9.8}}$

t=6.39 sec

The penny will hit the ground at 6.39 seconds

4 0

3 years ago