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svp [43]
3 years ago
9

The following phosphorus sulfides are known: P4S3, P4S7, and P4SIO. Do these compounds obey the law of multiple proportions?

Chemistry
1 answer:
AleksAgata [21]3 years ago
5 0

<u>Answer:</u> The given compounds obeys Law of multiple proportions.

<u>Explanation:</u>

Law of multiple proportions states that when two elements combine to form two or more compounds in more than one proportion. The mass of one element that combine with a given mass of the other element are present in the ratios of small whole number. <u>For Example:</u> Cu_2O\text{ and }CuO

We are given:

Three compounds having chemical formulas of P_4S_3,P_4S_7\text{ and }P_4S_{10}

In the given compounds, mass ratio of phosphorus and sulfur are:

  • <u>Ratios of mass of elements in P_4S_3</u>

Mass of phosphorus = (4 × 31) = 124 g/mol

Mass of sulfur = (3 × 32) = 96 g/mol

Mass ratio of phosphorus and sulfur in P_4S_3 is 124 : 96

  • <u>Ratios of mass of elements in P_4S_7</u>

Mass of phosphorus = (4 × 31) = 124 g/mol

Mass of sulfur = (7 × 32) = 224 g/mol

Mass ratio of phosphorus and sulfur in P_4S_7 is 124 : 224

  • <u>Ratios of mass of elements in P_4S_{10}</u>

Mass of phosphorus = (4 × 31) = 124 g/mol

Mass of sulfur = (10 × 32) = 320 g/mol

Mass ratio of phosphorus and sulfur in P_4S_3 is 124 : 320

As, the mass of phosphorus is fixed, so the mass ratio of sulfur in both the compounds must be in whole number ratio.

Mass ratio of sulfur in both the compounds =  96 : 224 : 320 = 3 : 7 : 10

Hence, the given compounds obeys Law of multiple proportions.

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The Density of pure carbon in Diamond form is 3.52 g/cm^3. How many cubic inches would 23.7 moles of pure diamond occupy?
Vedmedyk [2.9K]

Answer : The volume of pure diamond is 0.493inch^3

Explanation : Given,

Density of pure carbon in diamond = 3.52g/cm^3

Moles of pure diamond = 23.7 moles

Molar mass of carbon = 12 g/mol

First we have to calculate the mass of carbon or pure diamond.

\text{ Mass of carbon}=\text{ Moles of carbon}\times \text{ Molar mass of carbon}

Molar mass of carbon = 12 g/mol

\text{ Mass of carbon}=(23.7moles)\times (12g/mole)=284.4g

Now we have to calculate the volume of carbon or pure diamond.

Formula used:

Density=\frac{Mass}{Volume}

Now putting all the given values in this formula, we get:

3.52g/cm^3=\frac{284.4g}{Volume}

Volume = 80.8cm^3

As we know that:

1cm^3=0.061inch^3

So,

Volume = 0.061\times 80.8inch^3

Volume = 0.493inch^3

Therefore, the volume of pure diamond is 0.493inch^3

5 0
3 years ago
An atom of 24/11 na decays by gamma decay which atom is left after the decay
hammer [34]

Answer:

Hello There!!

Explanation:

The atom is still 24Na.

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6 0
2 years ago
Consider the following reaction where Kc = 1.80×10-2 at 698 K:
Klio2033 [76]

Answer:

The system is not in equilibrium and the reaction must run in the forward direction to reach equilibrium.

Explanation:

The reaction quotient Qc is a measure of the relative amount of products and reagents present in a reaction at any given time, which is calculated in a reaction that may not yet have reached equilibrium.

For the reversible reaction aA + bB⇔ cC + dD, where a, b, c and d are the stoichiometric coefficients of the balanced equation, Qc is calculated by:

Qc=\frac{[C]^{c}*[D]^{d}  } {[A]^{a}*[B]^{b}}

In this case:

Qc=\frac{[H_{2} ]*[I_{2} ] } {[HI]^{2}}

Since molarity is the concentration of a solution expressed in the number of moles dissolved per liter of solution, you have:

  • [H_{2} ]=\frac{2.09*10^{-2} moles}{1 Liter}=2.09*10⁻² \frac{moles}{liter}
  • [I_{2} ]=\frac{4.14*10^{-2} moles}{1 Liter}=4.14*10⁻² \frac{moles}{liter}
  • [I_{2} ]=\frac{0.280 moles}{1 Liter}= 0.280 \frac{moles}{liter}

So,

Qc=\frac{2.09*10^{-2} *4.14*10^{-2}  } {0.280^{2} }

Qc= 0.011

Comparing Qc with Kc allows to find out the status and evolution of the system:

If the reaction quotient is equal to the equilibrium constant, Qc = Kc, the system has reached chemical equilibrium.

If the reaction quotient is greater than the equilibrium constant, Qc> Kc, the system is not in equilibrium. In this case the direct reaction predominates and there will be more product present than what is obtained at equilibrium. Therefore, this product is used to promote the reverse reaction and reach equilibrium. The system will then evolve to the left to increase the reagent concentration.

If the reaction quotient is less than the equilibrium constant, Qc <Kc, the system is not in equilibrium. The concentration of the reagents is higher than it would be at equilibrium, so the direct reaction predominates. Thus, the system will evolve to the right to increase the concentration of products.

Being Qc=0.011 and Kc=1.80⁻²=0.018, then Qc<Kc. <u><em>The system is not in equilibrium and the reaction must run in the forward direction to reach equilibrium.</em></u>

8 0
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Does the bowling ball have more potential energy or kinetic energy as it is halfway through its fall? Why?
ahrayia [7]

Answer:

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Explanation:

I think the kinetic energy is 75 percent while the potential energy is 25 percent

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How many carbon atoms are in 15.0 grams of sucrose (C12H22O11)
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