Please make the following calculation and round your

a glass of ice at 0 degrees Celsius changes to a glass of water at 0 degrees Celsius what caused the ice to change to water

Tanya [424]

Thermal energy was absorbed.

6 0

4 years ago

Copper2 nitrate > nitrogen dioxide + copper2 oxide+ oxygen

erastovalidia [21]

Cu(NO3)2>NO2+CuO+O2 balanced: 2Cu(NO3)2=4NO2+2CuO+O2

3 0

3 years ago

one of your classmates is having trouble understanding ions, he explain the formation of a cation like this: "when you add an el

Irina-Kira [14]

Electrons carry a negative charge, so when you add on to the electron, the ion gets more negative.
hope this helps!

8 0

3 years ago

3 Cu + 8HNO3 g 3 Cu(NO3)2 + 2 NO + 4 H2O

Ksivusya [100]

Considering the reaction stoichiometry, the amount of moles of NO that is produced when 27 moles of HNO₃ react is 6.75 moles.

<h3 /><h3>Reaction stoichiometry</h3>

The balanced reaction is:

3 Cu + 8 HNO₃ → 3 Cu(NO₃)₂ + 2 NO + 4 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Cu: 3 moles
HNO₃: 8 moles
Cu(NO₃)₂: 3 moles
NO: 2 moles
H₂O: 4 moles

<h3>Amount of moles of NO produced</h3>

It is possible to determine the the amount of moles of NO produced by a rule of three: if by stoichiometry 8 moles of HNO₃ produce 2 moles of NO, if 27 moles of HNO₃ react how many moles of NO will be formed?

$amount of moles of NO=\frac{27 moles of HNO_{3} x 2 moles of NO}{8 moles of HNO_{3}}$

<u><em>amount of moles of NO= 6.75 moles</em></u>

In summary, the amount of moles of NO that is produced when 27 moles of HNO₃ react is 6.75 moles.

Learn more about reaction stoichiometry:

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4 0

3 years ago

If 155 J of heat energy is applied to a block of silver weighing 27.9 g, by how many degrees will the temperature of the silver

Brilliant_brown [7]

Answer:

The temperature of silver increase by 23.15 °C.

Explanation:

Given data:

Heat added = 155 j

Mass of silver = 27.9 g

How many degree temperature increase = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Specific heat capacity of silver is = 0.240 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Now we will put the values in formula.

155 j = 27.9 g × 0.240 j/g.°C × ΔT

155 j = 6.696 j/°C × ΔT

ΔT = 155 j /6.696 j/°C

ΔT = 23.15 °C

3 0

3 years ago