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Vlad1618 [11]
3 years ago
13

Scientists use their to make observations

Chemistry
2 answers:
frosja888 [35]3 years ago
5 0
Microscopes?
Scanners?
Transmitters?
Cameras?
Hand lens?
There are a lot
andreev551 [17]3 years ago
3 0
Eyes?
Tools?
Experience?
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From the formula MgO how do you know that Mg is the metal?
Damm [24]

In binary ionic compounds the name of the cation (Metal) is first, so that’s how you know.

5 0
3 years ago
The study of Environmental Science includes which of the following?
stepan [7]

Answer:

Hi, There! the Correct Answer is below!

C.)interactions between humans and living and non-living things in the environment

Explanation:

Environmental scientists study subjects like the understanding of earth processes, evaluating alternative energy systems, pollution control and mitigation, natural resource management, and the effects of global climate change. ... Environmental scientists bring a systems approach to the analysis of environmental problems.

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Have a wonderful Day :)

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3 0
3 years ago
Read 2 more answers
If an atom of zinc has a mass of 64 it has how many neutrons
sveta [45]
Answer:

no of neutron = atomic mass - atomic number

Explanation:

here
atomic mass = 64
atomic number = 30

no of neutron = <span>64−30</span>

no of neutron = 34


3 0
3 years ago
A student has a sample of aluminum that has a mass of 27 g and a volume of 10cm3. What is the density of aluminum​
Anestetic [448]

Answer:

270 g/cm^3

Explanation:

d = mv

d = 27 g × 10cm^3

d = 270 g/cm^3

6 0
3 years ago
A solution is made containing 14.6g of CH3OH in 185g H2O.1. Calculate the mole fraction of CH3OH.2. Calculate the mass percent o
Andre45 [30]

Answer:

* x_{CH_3OH}=0.0425

* \%m/m_{CH_3OH}=7.31\%

* m=2.46m

Explanation:

Hello,

In this case, for the mole fraction of methanol we use the formula:

x_{CH_3OH}=\frac{n_{CH_3OH}}{n_{CH_3OH}+n_{water}}

Thus, we compute the moles of both water (molar mass 18 g/mol) and methanol (molar mass 32 g/mol):

n_{CH_3OH}}=14.6g*\frac{1mol}{32g}=0.456molCH_3OH \\\\n_{water}}=185g*\frac{1mol}{18g}=10.3molH_2O

Hence, mole fraction is:

x_{CH_3OH}=\frac{0.456mol}{0.456mol+10.3mol}\\\\x_{CH_3OH}=0.0425

Next, mass percent is:

\%m/m_{CH_3OH}=\frac{m_{CH_3OH}}{m_{CH_3OH}+m_{water}}*100\%\\\\\%m/m_{CH_3OH}=\frac{14.6g}{14.6g+185g}*100\%\\\\\%m/m_{CH_3OH}=7.31\%

And the molality, considering the mass of water in kg (0.185 kg):

m=\frac{n_{CH_3OH}}{m_{water}} =\frac{0.456mol}{0.185kg}\\ \\m=2.46m

Regards.

7 0
3 years ago
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