3 years ago

Calculate the solubility of cux(ksp=[cu2 ][x2?]=1.27×10?36 in a solution that is 0.120 m in nacn.

1 answer:

4 0

The dissociation reaction of CuX is as follows:

CuX = Cu2+ + X2-

The solubility product constant is given as 1.27×10^36 and is in terms of the concentration of the ionic species, it would be:

Ksp = 1.27×10^36 = [cu2 ][x2-] = [x][x]
x = 1.13x10^18 M

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