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Arte-miy333 [17]
3 years ago
8

Estimate the total mass of the Earth’s atmosphere. (The radius of the Earth is 6.37 3 106 m, and atmospheric pressure at the sur

face is 1.013 3 105 Pa.)
Physics
1 answer:
ser-zykov [4K]3 years ago
7 0

Answer:

m = 5.27e18 kg

Explanation:

The pressure of a fluid is the weigth of a column of that fluid over base of that column.

P = \frac{weight}{base}

The weight of the column is its mass multiplied by the acceleration of gravity. The acceleration of gravity varies with height, however the variation is small and can be ignored, consifering the acceleration of gravity constant.

weight = m * g

So:

P = \frac{m * g}{base}

If we consider the entirety of the atmosphere as a single column the base would be the surface of Earth. Approximating Earth as a sphere:

S = 4 * \pi * r^2

Now, we can obtain the mass of the atmosphere:

m = \frac{4 * P * \pi * r^2}{g}

m = \frac{4 * 1 01325* \pi * 6373106^2}{9.81} = 5.27e18 kg

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forsale [732]

Answer:

Force, F = 187.42 N

Explanation:

It is given that,

Mass of boy, m = 30 kg

Acceleration due to gravity, a=9.8\ m/s^2

Radius of curvature of the roller coaster, r = 15 m

Speed of the car, v = 7.3 m/s

The force acting on the boy are force of gravity and the centripetal force. The net force acting on him is as follows :

F=mg-\dfrac{mv^2}{r}

F=m(g-\dfrac{v^2}{r})

F=30\times (9.8-\dfrac{(7.3)^2}{15})

F = 187.42 N

So, he press against the seat with a force is 187.42 N. Hence, this is the required solution.

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3 years ago
What constant acceleration (in ft/s2) is required to increase the speed of a car from 27 mi/h to 50 mi/h in 5 seconds
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Answer:

6.746 ft/s^2

Explanation:

v(t)=50

v(0)=27

t=5/3600 = 1/720 hours

v(t)-v(0)= a(t-0)

50-27= a(1/720)

a= 23*720= 16560 mi/h^2

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Which describes Michael Faraday’s work with electricity and magnetism?
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Answer: D. It is a SUSPENSION

Explanation:

SUSPENSION

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