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Hoochie [10]
4 years ago
7

Using hookes law what happens when the displacement is tripled?

Physics
1 answer:
Wewaii [24]4 years ago
7 0
Hooke's law stated that the Force (F) exerted to compress or elongate an object to a distance (D) is proportional to that distance (D) where a certain proportionality constant, k, also known as hooke's constant is accounted for. In this case, if the displacement is tripled, the force required will also be tripled.
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A merter stick pivoted at its center has a 150gm mass suspended at its 20cm mark. a) Where should an 100gm mass be placed to pro
IgorLugansk [536]

Answer:1) 100 gm mass should be placed at 95 cm mark.

2) Mass of 112.5 gm should be placed at 90 cm mark.

Explanation:

For equilibrium of the meter stick the sum of the moment's generated by the masses should be equal and opposite

Answer to part b)

Since a meter stick is 100 cm long and it is pivoted at it's center i.e at 50 cm

Thus

1) Moment generated by 100 gm mass about center = M_{1}=m_{1}g\times r_{1}\\\\M_{1}=0.15\times 9.81\times 0.3=0.44145Nm

Let a mass 'm' be placed at 90 cm mark thus moment it generates equals

M_{2}=m\times 9.81\times 0.4=3.924m

Equating both the moments we get

0.44145=3.924m\\\\\therefore m=\frac{0.44145}{3.924}\times 1000grams\\\\\therefore m= 112.5grams

Answer to part a)

Let the 100 grams weight be placed at a distance 'x' right of center

Moment generated by 100 grams weight equals

M_{1}=0.1\times 9.81\times x

equating the moments of the forces we get

0.1\times 9.81\times x=0.15\times 0.3\times 9.81

\therefore x=\frac{0.4415}{.981}=45centimeters

thus the mass of 100 gm should be placed at 95 cm mark in the scale.

8 0
4 years ago
Ther are several differences between chemical and physical changes. Which process is an example of a chemical change?
slamgirl [31]

Answer:

A physical change is the change of the shape or color.

Explanation:

4 0
3 years ago
Read 2 more answers
A blue supergiant star has surface temperature 27 kK and has total power output 100000 times that of the Sun.
Free_Kalibri [48]

Answer:

Wien peak ( λmax ) is 107.40 nm

radius of super giant is 1.086 ×10^{10} m

Explanation:

given data

temperature 27 kK

power = 100000 times of Sun

Sun radius =  6.96 × 10^8 m

to find out

Wien peak ( λmax ) and radius of supergiant (r)

solution

we will apply here first wien law to find Wien peak  that is

λmax = b / t

λmax = 2.9 × 10^{-3} / 27000 = 1.0740 × 10^{-7}

so Wien peak ( λmax ) is 107.40 nm

and

now we apply steafay law that is

P = σ × A × T^{4}   .........................1

and we know total power output 100000 time of Sun

so we say  

4πr²sT^{4}  = 100000 × 4πR²sTs^{4}

r² = 100000  × R²Ts^{4} / T^{4}

put here value

r² = 100000  × (6.96×6000^{8} )² × 6000^{4} / 27000^{4}

r² = 1.18132 ×10^{20}

r = 1.086 ×10^{10} m

so radius of super giant is 1.086 ×10^{10} m

3 0
4 years ago
How long would it take a bus driver at 50 km/ h to travel 125km
poizon [28]

Answer:

About 30 minutes

Explanation:

4 0
3 years ago
A bullet is fired through a board 13.0 cm thick in such a way that the bullet's line of motion is perpendicular to the face of t
GREYUIT [131]

Answer:

392307.6923 m/s²

Explanation:

t = Time taken

u = Initial velocity = 560 m/s

v = Final velocity = 460 m/s

s = Displacement = 13 cm

a = Acceleration

From the equation of motion we have

v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{460^2-560^2}{2\times 13\times 10^{-2}}\\\Rightarrow a=-392307.6923\ m/s^2

The acceleration of the bullet as it passes through the board is -392307.6923 m/s²

5 0
3 years ago
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