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weeeeeb [17]
3 years ago
13

Starting circuit One battery. 2 light bulbs in parallel; switch What is the voltage across the battery? What is the voltage acro

ss light bulb 1? What is the voltage across light bulb 2?​
Physics
1 answer:
balu736 [363]3 years ago
5 0

Answer:

The voltage across light bulb 1 and light bulb 2 is the the same i.e V

Explanation:

In a parallel circuit, the Voltage is same across all the components of the circuit and the current flowing through each component is added to get the total current across the circuit.

Let us say, the voltage across the circuit is V. The voltage across light bulb 1 and light bulb 2 is the the same i.e V

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The motion of an electron is given by x(t)=pt3+qt2+r, with p = -2.3 m/s^3 ,q = +1.5 m/s^2 , and r = +9.0 m.A) Determine its velo
alexandr402 [8]

Answer:

v(0)=0\\v(1)=-3.9\ m/s\\v(2)=-21.6\ m/s\\v(3)=-53.1\ m/s

Explanation:

<u>Instant Velocity </u>

Given the position as a function of time x(t), the instant velocity is the derivative of the function:

v(t)=x'(t)

We are given the position as

x(t)=-2.3t^3+1.5t^2+9

The derivative of x is

v(t)=x'(t)=-6.9t^2+3.0t

A) Let's compute v(0)

v(0)=-6.9(0)^2+3.0(0)=0

B)  

v(1)=-6.9(1)^2+3.0(1)

v(1)=-3.9\ m/s

C)

v(2)=-6.9(2)^2+3.0(2)

v(2)=-21.6\ m/s

D)

v(3)=-6.9(3)^2+3.0(3)

v(3)=-53.1\ m/s

4 0
3 years ago
3.A golf ball is hit of it’s tee, 200m down the fairway.
Alinara [238K]

<u>Answers:</u>


3. The diagrams showing the forces acting on the golf ball are in the figure attached. Let’s have a detailed look:


a) Here the ball is under 2 forces:


F1 which is called The Normal force and is perpendicular to the surface of the tee where the ball rests


-F1, related to the gravity force, to the weight of the ball, and has the same magnitude, but the opposite direction (That’s why it has a negative sign).



In this case the sum of the forces is 0



b) Here we have again forces F1 and –F1, but in this very moment the club strikes the ball and we have:


F2, the force of the strike





c) While the ball is in its flight, it is under the following forces:


F1, the force of the lift through the air


-F2, the gravity force

-F3, the force of air resistance, also called drag


F4, the tangencial force of the ball flight




4. Here are the sizes and directions of the resultant forces:


i)Two forces of the same magnitude or size are applied to this block, but in opposite directions (in the x-axis). This is expressed as:



F=-10N+10N=0 The resulting force is zero



ii) Two forces of different size and opposite directions in the y-axis are applied to this block. The sum of the forces is:



F=30N-40N=-10N This means the resulting force is 10N applied downwards



iii) In this case the only force applied to the block is -5N applied downwards



iv) Here there are four forces applied to the block.  

In the y-axis we have to forces of the same size but opposite directions:



F1=10N-10N=0 This means the applied force in the y-axis is zero



In the x-axis we have two forces of different size and opposite directions:



F2=-15N+10N=-5N This means the resulting force is applied to the –x-side



4 0
3 years ago
A low-velocity flow over a smooth stream bed produces a
Reika [66]
Produces<span> V-shaped valley, steep sides Rapids 

</span>
4 0
3 years ago
Describe the path that light waves take when you see your image in a mirror
ICE Princess25 [194]
Describe the path light waves take when you see your image in the mirror?

<span>light strikes your face and bounces off of it. then, light is reflected off your face and into the mirror. i is hen reflected into your eyes.</span>

7 0
3 years ago
Solve for velocity in A car has traveled 456 meters in 45 seconds while driving east on Broad Street. What is the velocity of th
OLEGan [10]

Answer:

10.13

Explanation:

take note that velocity is distance over time (v=\frac{d}{t}) so you do 456(distance)÷45(time)= 10.13

3 0
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