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AleksAgata [21]
3 years ago
9

A wheel is rotating in a counterclockwise direction about its center. Then suppose the rotation rate slows to zero and then spee

ds up to an even greater value in the opposite direction. For an object attached to the rim of the wheel: (the equation for centripetal acceleration aC = vt2/r, where vt = tangential velocity and r is the wheel radius)
What happens to the direction of the centripetal acceleration vector (what’s the overall change in the direction)?
Physics
2 answers:
Marat540 [252]3 years ago
6 0

Answer:

Explanation:

When a body moves on a circular path , it undergoes a centripetal acceleration which is directed towards the centre . Whether the body moves clockwise or anticlockwise , the direction of centripetal acceleration will always oriented towards the centre.

The variation in  tangential velocity will only change the magnitude of the acceleration but the direction of the centripetal acceleration will always be directed towards the centre.

So in the given case , change in the direction of rotation will not change the direction of centripetal acceleration. It will remain unchanged towards the centre.

overall change in direction of centripetal acceleration  is zero.

Leni [432]3 years ago
3 0

Answer:

Answer:

Explanation:

When a body moves on a circular path , it undergoes a centripetal acceleration which is directed towards the centre . Whether the body moves clockwise or anticlockwise , the direction of centripetal acceleration will always oriented towards the centre.

The variation in  tangential velocity will only change the magnitude of the acceleration but the direction of the centripetal acceleration will always be directed towards the centre.

So in the given case , change in the direction of rotation will not change the direction of centripetal acceleration. It will remain unchanged towards the centre.

overall change in direction of centripetal acceleration  is zero.

Explanation:

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When a cricket ball is thrown vertically upwards, it reaches a maximum height of 15 metres. (a) What was the initial speed of th
Gelneren [198K]

Answer:

The velocity of the cricket ball is 17.32 m/s

Time is taken by the ball to reach the highest point = 0.8660 seconds

Explanation:

The cricket ball can be seen and treated as a projectile in this case

The maximum height attained by a projectile in motion can be calculated using the formula:

h = \frac{v^2 sin^2 \theta }{2g}

In any projectile problem, once we know see that the object was released vertically upwards, we need to know that this means that the angle of projection is 90 degrees, and sin 90 is = 1

hence, h will be modified to become

h = \frac{v^2  }{2g}

v = \sqrt{2gh}

We are given that h = 15m and g = 10m/s2

v = \sqrt{2 \times 10 \times 15} = 17.32m/s

The velocity of the cricket ball is 17.32 m/s

B. We can get the time it took to reach the highest point by dividing

time = distance/speed

Time = 15/17.32 = 0.8660 seconds

6 0
3 years ago
• How does AC work?
Juli2301 [7.4K]
AC reverses the current in periods, and the current flows in 2 directions. 
DC only flows in one direction and is constant. 

AC is typically used to transfer power over long distances from a generator to your home, stepping it up after it's generated to send it over the distance, then stepping it back down so that it is usable in your home.

DC is used typically inside of devices, as it sends a certain amount of electricity through the wires.

Nicolas Tesla, was ripped off by Edison to replace his DC stations with AC instead. ^^
4 0
3 years ago
Can someone explain this
Alborosie

Answer:

gravity

Explanation:

That would make the most sense from what I know

8 0
3 years ago
Read 2 more answers
An object moves with a speed of 30 km/h for 15 minutes and then with a speed of 60km/h for the next 15 minutes. Find the total d
Finger [1]

Answer:

Total distance = 22.5 kilometers

Explanation:

Let the first distance be A.

Let the second distance be B

Given the following data;

Speed A = 30km/h

Time A = 15 minutes to hours = 15/60 = 0.25 hour

Speed B = 60km/h

Time B = 15 minutes to hours = 15/60 = 0.25 hour

Now, to find the respective distance traveled;

Distance A = speed A * time A

Distance A = 30 * 0.25

Distance A = 7.5 km

Distance B = speed B * time B

Distance B = 60 * 0.25

Distance B = 15 km

Next, we calculate the total distance traveled;

Total distance = Distance A + distance B

Total distance = 7.5 + 15

Total distance = 22.5 kilometers.

Therefore, the total distance covered by the object is 22.5 kilometers.

5 0
3 years ago
Suppose a wheel with a tire mounted on it is rotating at the constant rate of 2.55 times a second. A tack is stuck in the tire a
earnstyle [38]

Answer:

Tangential speed = 5.72 m/s

Centripetal acceleration = 91.6\text{ m/s}{}^2

Explanation:

The tangential speed, V, is given by

v=\omega r

where \omega is the angular speed and is given by 2\pi f (f is the angular frequency or frequency of rotation)

Thus,

v=2\pi f r = 2\times3.14\times2.55\times0.357 = 5.72\text{ m/s}

The centripetal acceleration,a, is given by

a=\dfrac{v^2}{r}

a=\dfrac{5.72^2}{0.357} = 91.6\text{ m/s}{}^2

7 0
4 years ago
Read 2 more answers
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