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AleksAgata [21]
3 years ago
9

A wheel is rotating in a counterclockwise direction about its center. Then suppose the rotation rate slows to zero and then spee

ds up to an even greater value in the opposite direction. For an object attached to the rim of the wheel: (the equation for centripetal acceleration aC = vt2/r, where vt = tangential velocity and r is the wheel radius)
What happens to the direction of the centripetal acceleration vector (what’s the overall change in the direction)?
Physics
2 answers:
Marat540 [252]3 years ago
6 0

Answer:

Explanation:

When a body moves on a circular path , it undergoes a centripetal acceleration which is directed towards the centre . Whether the body moves clockwise or anticlockwise , the direction of centripetal acceleration will always oriented towards the centre.

The variation in  tangential velocity will only change the magnitude of the acceleration but the direction of the centripetal acceleration will always be directed towards the centre.

So in the given case , change in the direction of rotation will not change the direction of centripetal acceleration. It will remain unchanged towards the centre.

overall change in direction of centripetal acceleration  is zero.

Leni [432]3 years ago
3 0

Answer:

Answer:

Explanation:

When a body moves on a circular path , it undergoes a centripetal acceleration which is directed towards the centre . Whether the body moves clockwise or anticlockwise , the direction of centripetal acceleration will always oriented towards the centre.

The variation in  tangential velocity will only change the magnitude of the acceleration but the direction of the centripetal acceleration will always be directed towards the centre.

So in the given case , change in the direction of rotation will not change the direction of centripetal acceleration. It will remain unchanged towards the centre.

overall change in direction of centripetal acceleration  is zero.

Explanation:

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Inertia is based only on an objects <br> A. Mass<br> B. Net force <br> C. Velocity <br> D. Weight
coldgirl [10]

Answer:

A. Mass

Explanation:

Inertia is the resistance of an object to any change in its velocity. Inertia depends only on the mass of the object: the greater the mass, the larger the inertia of the object, because it will be more difficult to change the velocity of the object.

An example to better understand: assume there is a golf ball rolling with a certain speed, and a car moving with the same speed. If we want to stop the two objects, we will need a much larger force for the car, because its mass is much greater than the gold ball, so it has much more inertia than the golf ball.

6 0
4 years ago
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What are the 3 units we use to measure the universe??
ioda
If you mean what types of measurements are used to measure in outer space, I believe it’s light-year, astronomical unit and intergalactic measurements, but I’m not completely sure.

Hopefully this helps...
6 0
3 years ago
Consider a short time span just before and after the spark plug in a gasoline engine ignites the fuel-air mixture and releases 1
Tju [1.3M]

Answer:

Temperature after ignition=7883.205 K

Explanation:

The number of moles is,

n=PV/RT

=(1.18x10^6)(47.9x10^-6)/8.314(325)

= 0.0209 moles

a) In this process volume is constant

Q=U

=nCv.dT

dT= Q/nCv

=1970/(1.5x8.314)(0.0209)

= 7558.205 K

The final temperature is,

= 7558.205+325

= 7883.205 K

5 0
3 years ago
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evaluate the statement heavy things sink and light things float. is the statement true or false? if false rewrite the statement
aliya0001 [1]

Answer:

False

Explanation:

It depends on the density of an object, not the wight.

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3 years ago
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When using a calorimeter, the initial temperature of a metal is 70.4C. The initial temperature of the water is 23.6C. At the end
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1) 29.8 C

At the beginning, the metal is at higher temperature (70.4 C) while the water is at lower temperature (23.6 C). When they are put in contact, the metal transfers heat to the water, until they reach thermal equilibrium: at thermal equilibrium the two objects (the metal and the water have same temperature). Therefore, since the temperature of the water at thermal equilibrium is 29.8 C, the final temperature of the metal must be the same (29.8 C).

2) 6.2 C

The temperature change of the water is given by the difference between its final temperature and its initial temperature:

\Delta T = T_f - T_i

where

T_f = 29.8 C\\T_i = 23.6 C

Substituting into the formula,

\Delta T=29.8 C-23.6 C=6.2 C

And the positive sign means that the temperature of the water has increased.

3) -40.6 C

The temperature change of the metal is given by the difference between its final temperature and its initial temperature:

\Delta T = T_f - T_i

where

T_f = 29.8 C\\T_i = 70.4 C

Substituting into the formula,

\Delta T=29.8 C-70.4 C=-40.6 C

And the negative sign means the temperature of the metal has decreased.

5 0
4 years ago
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