Answer:
50000 μT
Explanation:
From the given information:
the diameter of the loop = 1.0 mm = 0.001 m
no of turns (N) = 200
current (I) = 0.199 A
radius = d/2 = 0.001/2
= 5 × 10⁻⁴ m
Recall that;
the magnetic field at the centre of circular wire is:
= 0.05 T
= 50000 μT
Since the centre of the earth's magnetic field is given to be equal to the magnetic field produced by the wire, then:
the earth's magnetic field = 50000 μT
Answer:
ΔR = 9 s
Explanation:
To calculate the propagation of the uncertainty or absolute error, the variation with each parameter must be calculated and the but of the cases must be found, which is done by taking the absolute value
The given expression is R = 2A / B
the uncertainty is ΔR = | 
| ΔA + | 
| ΔB
we look for the derivatives
= 9 / B
= 9A ( 
)
we substitute
ΔR = 
ΔA + 
ΔB
the values are
ΔA = 2 s
ΔB = 3 s
ΔR = 
2 + 
3
ΔR = 1.636 + 7.14
ΔR = 8,776 s
the absolute error must be given with a significant figure
ΔR = 9 s
I think the answer is A
.
im not the best with physics but i think its right
Answer:
257 kN.
Explanation:
So, we are given the following data or parameters or information in the following questions;
=> "A jet transport with a landing speed
= 200 km/h reduces its speed to = 60 km/h with a negative thrust R from its jet thrust reversers"
= > The distance = 425 m along the runway with constant deceleration."
=> "The total mass of the aircraft is 140 Mg with mass center at G. "
We are also give that the "aerodynamic forces on the aircraft are small and may be neglected at lower speed"
Step one: determine the acceleration;
=> Acceleration = 1/ (2 × distance along runway with constant deceleration) × { (landing speed A)^2 - (landing speed B)^2 × 1/(3.6)^2.
=> Acceleration = 1/ (2 × 425) × (200^2 - 60^2) × 1/(3.6)^2 = 3.3 m/s^2.
Thus, "the reaction N under the nose wheel B toward the end of the braking interval and prior to the application of mechanical braking" = The total mass of the aircraft × acceleration × 1.2 = 15N - (9.8 × 2.4 × 140).
= 140 × 3.3× 1.2 = 15N - (9.8 × 2.4 × 140).
= 257 kN.
