Draw the distance time graph for a body at rest
2 answers:
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Answer:
Distance, d = 99990 meters
Explanation:
It is given that,
Speed of the train, v = 200 km/h = 55.55 m/s
Time taken, t = 1800 s
Let d is the distance covered by the train. We know that the speed of an object is given by total distance covered divided by total time taken. Mathematically, it is given by :
d = 99990 m
So, the distance covered by the train is 99990 meters. Hence, this is the required solution.
Answer:
a) 9.00 m b) 6.00 m/s c) 12.00 m/s
Explanation:
a) If the acceleration is constant, and we know that the displacement during the first second was 3.00 m, as the boulder (assumed that we can treat it as a point mass) started from rest, we can say the following:
Δx = = 3.00 m
As t = 1 s, replacing in the expression above, and solving for a, we have:
= 6.00 m/s²
In order to know how far it travels during the second second, we need to know the value of the speed after the first second, as it is the initial velocity when the second second begins:
vf = v₀ + a*t ⇒ vf = 0 + 6 m/s²*1s = 6.00 m/s
The total displacement, during the second second, will be as follows:
Δx = v₀*t + = 6.00m/s*1s +
⇒ Δx = 9.00 m
b) At the end of the first second, the final speed can be obtained as follows:
vf = v₀ + a*t ⇒ vf = 0 + 6 m/s²*1s = 6.00 m/s
c) At the end of the second second, the final speed can be obtained as follows:
vf = v₀ + a*t ⇒ vf = 0 + 6 m/s²*2s = 12.00 m/s