V = frequency * wavelength
v = 80 * 4
v = 320m/s
Answer:
The acceleration of the sliding toboggan is, a = 4.9 m/s²
Explanation:
Given data,
The total weight of the toboggan, W = 1300 N
The slope is, Ф = 30°
The acceleration of a body under the influence of the gravitational field does not depend on its mass, size and shape in the absence of the air resistance.
Therefore,
The acceleration of the toboggan is given by the formula,
a = g Sin Ф
Substituting the given values in the above equation,
a = 9.8 x Sin 30°
= 4.9 m/s²
Hence, the acceleration of the sliding toboggan is, a = 4.9 m/s²
Answer:
50 m
Explanation:
F = ma
10 N = (10 kg) a
a = 1 m/s²
Given:
v₀ = 0 m/s
a = 1 m/s²
t = 10 s
Find: Δx
Δx = v₀ t + ½ at²
Δx = (0 m/s) (10 s) + ½ (1 m/s²) (10 s)²
Δx = 50 m
