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Mashutka [201]
3 years ago
10

The correct name for molecule I is

Chemistry
1 answer:
givi [52]3 years ago
4 0

Answer:

c). 2-iodopropane

14) C). Fluoroethene

16) D). More chemically reactive

17) 1). High temperature combustion  - Dioxins/furans

2). Pulp and paper industry  - SO2(g)

3). Pesticides  - Phosphates

4). Sour gas plants - Nox(g)

Explanation:

The correct name for molecule I would be '2-iodopropane' where the number 2 reflects the position of iodine. There are three carbons and 8 hydrogen atoms which reflect that it is an alkane compound. In the given carbon chain. In this chain of three carbons, iodine is present on the second carbon. Therefore, option C is the correct answer.

14). The appropriate name for molecule III exemplifies Fluoroethene as it consists of two carbons due to which it belongs to the 'ethane' group and it bears the prefix 'fluoro as it belongs to fluorine group and the suffix '-ene' due to double bond.

16). Synthetic hydrocarbons are 'more chemically reactive' and therefore, it generates greenhouse gases and leads to climate change, global warming, depletion of the ozone layer, etc.

17). 1). Dioxins are generated as a result of high-temperature combustion processes like commercial waste incineration or burning of fuels.

2). Pulp and paper industry releases various gases like nitrogen oxide, sulfur dioxide SO2(g), carbon dioxide, etc.

3). Phosphate is the pollutant released from pesticides that badly affects the fertility of the soil.

4). Nox(g) nitrogen oxide released by sour gas plants and coal-fired emissions is a major contributor to increased greenhouses gases and global warming.

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Roman55 [17]

Gold.

Silver.

Iron.

Copper.

Nickel.

Aluminum.

Mercury( Liquid metal)

Titanium.

7 0
3 years ago
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Which element has chemical properties that are most similar to the chemical properties of sodium?
DochEvi [55]
It's K since K and Na are in the same family
8 0
3 years ago
How many atoms are in 1.4 moles of H3PO4?
sdas [7]
<h3>Answer:</h3>

8.4 × 10²³ atoms H₃PO₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 1.4 moles H₃PO₄

[Solve] atoms H₃PO₄

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                      \displaystyle 1.4 \ mol \ H_3PO_4(\frac{6.022 \cdot 10^{23} \ atoms \ H_3PO_4}{1 \ mol \ H_3PO_4})
  2. [DA] Multiply [Cancel out units]:                                                                    \displaystyle 8.4308 \cdot 10^{23} \ atoms \ H_3PO_4

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

8.4308 × 10²³ atoms H₃PO₄ ≈ 8.4 × 10²³ atoms H₃PO₄

3 0
3 years ago
A solution is prepared by mixing 93.0 mL of 5.00 M HCl and 37.0 mL of 8.00 M HNO3. Water is then added until the final volume is
Charra [1.4K]

Answer:

[H^{+}] = 0.761 \frac{mol}{L}

[OH^{-}]=1.33X10^{-14}\frac{mol}{L}

pH = 0.119

Explanation:

HCl and HNO₃ both dissociate completely in water. A simple method is to determine the number of moles of proton from both these acids and dividing it by the total volume of solution.

n_{H^{+} } from HCl = [HCl](\frac{mol}{L}). V_{HCl}(L)  \\ n_{H^{+} } from HNO_{3}  = [HNO_{3}](\frac{mol}{L}). V_{HNO_{3}}(L)

Here, n is the number of moles and V is the volume. From the given data moles can be calculated as follows

n_{H^{+} } from HCl = (5.00)(0.093)

n_{H^{+} } from HCl = 0.465 mol

n_{H^{+} } from HNO_{3}  = (8.00)(0.037)

n_{H^{+} } from HNO_{3}  = 0.296 mol

n_{H^{+}(total) } = 0.296 + 0.465

n_{H^{+}(total) } = 0.761 mol

For molar concentration of hydrogen ions:

[H^{+}]  = \frac{n_{H^{+}}(mol)}{V(L)}

[H^{+}] = \frac{0.761}{1.00}

[H^{+}] = 0.761 \frac{mol}{L}

From dissociation of water (Kw = 1.01 X 10⁻¹⁴ at 25°C) [OH⁻] can be determined as follows

K_{w} = [H^{+} ][OH^{-} ]

[OH^{-}]=\frac{Kw}{[H^{+}] }

[OH^{-}]=\frac{1.01X10-^{-14}}{0.761 }

[OH^{-}]=1.33X10^{-14}\frac{mol}{L}

The pH of the solution can be measured by the following formula:

pH = -log[H^{+} ]

pH = -log(0.761)

pH = 0.119

5 0
3 years ago
An element has an atomic number of 77, an atomic mass of 152, and is considered electrically neutral. How many protons, neutrons
hammer [34]

Answer:

77 protons

77 electrons

75 neutrons

Explanation:

5 0
3 years ago
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