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yanalaym [24]
4 years ago
10

Early transition metals are often found naturally as oxides, whereas late transition metals are often found naturally as sulfide

s. Find specific examples and use concepts from this chapter and from earlier chapters in the course to offer an explanation for the difference.
Chemistry
1 answer:
vlabodo [156]4 years ago
3 0

Answer:

Early transition metals- found on the left side of the periodic table (group 3-7), so called because they form the first part of the transition phase.These metals have less electrons than late transition metals, therefore their last valance matches their group number. Examples of early transitions metals are,Scandium, Titanium, and Manganese

Late transition metals- fast reacting metals, because their maximum valance shells are full, therefore having accessible oxidation states.Examples are Nickle, Silver, and Cobalt

Explanation:

Transition metal found in the middle of the periodic table. The IUPAC defines these metals,as metals whose atoms have a relatively full d-shell

Early and late transition metals are different due to their oxidation states.

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Chemistry question. Image attached.
Stells [14]

Answer:

The answer to your question is given below

Explanation:

The balanced equation for the reaction is given below:

CaO(s) + CH4(g) + 2H2O(g) <=> CaCO3(s) + 4H2(g)

1. Writing an expression for the equilibrium constant, K.

The equilibrium constant, K for a reaction is simply the ratio of the concentration of the products raised to their coefficient to the concentration of the reactants raised to their coefficient.

Thus, we can write the equilibrium constant, K for the reaction as follow:

CaO(s) + CH4(g) + 2H2O(g) <=> CaCO3(s) + 4H2(g)

K = [CaCO3] [H2]⁴ / [CaO] [CH4] [H2O]²

2. Based on the value of K, more products will be in the equilibrium mixture since the value of K is a positive large number.

6 0
3 years ago
What kind of changes are permanent and alter the identity of a substance
siniylev [52]
Chemical changes are permanent and alter the identity of a sustance
5 0
4 years ago
Read 2 more answers
The substance fluorine has the following properties: normal melting point: 53.5 K normal boiling point: 85.0 K triple point: 1.6
mihalych1998 [28]

Answer:

The true statements include;

- The sample is initially a gas.

- The final state of the substance is a solid.

- One or more phase changes will occur.

The untrue/false statements include;

- The liquid initially present will vaporize.

- The final state of the substance is a liquid.

Explanation:

A couple pieces of informatton on Fluorine is imitially provided.

The substance fluorine has the following properties: normal melting point: 53.5 K normal boiling point: 85.0 K triple point: 1.6×10-4 atm, 53.4 K critical point: 55 atm, 144.1 K

So, a question is now attached about a sample of Fluorine. A sample of fluorine at a pressure of 1.00 atm and a temperature of 90.3 K is cooled at constant pressure to a temperature of 49.3 K.

We are then told to examine a group of options to find the ones that are correct/apply.

Taking the options one at a time

- The sample is initially a gas.

The initial state of the Fluorine sample has its temperature at 90.3 K, which is above the gas' boiling point. Hence, the sample can be concluded to initially be a gas.

- The liquid initially present will vaporize.

The sample doesn't initially contain liquid. And even of it did, the temperature is cooled, not heated , Hence, this statement is wrong.

- The final state of the substance is a solid.

The sample of Fluorine moves from a temperature higher than boiling point (85.0 K), with the sample in gaseous form, to one that is at a lower temperature (49.3 K) than the gas' normal melting point (53.5 K).

At temperatures lower than melting point, a substance exists in the solid form. Hence, this statement is true. The final state of the substance is solid.

- One or more phase changes will occur.

In moving from 90.3 K to 49.3 K for the sample and passing through the substance's boiling and melting points (85.0 K and 53.5 K respectively) along the way, it is logical to conclude that there would be one or more phase changes will occur. This statement is true.

- The final state of the substance is a liquid.

This is false as we already established that the final state of the substance is a solid. Hence, this statement is false.

Hope this Helps!!!

7 0
4 years ago
Fracking involves the ______drilling to extract oil and natural gas from the rock. Select one: a. vertical b. lateral c. horizon
Shkiper50 [21]

Answer:

Fracking involves the ______drilling to extract oil and natural gas from the rock. Select one: a. vertical b. lateral c. horizontal

The answer is option C (horizontal)

Explanation:

Fracking commonly known as Hydraulic fracturing is an oil and gas production technique that has enabled the extraction of oil and gas from rock (shale rock).

A fracturing fluid typically water with additives is pumped under high pressure into the drilling pipe to widen fractures in the rock or to create new ones and and allow trapped gas or crude oil to flow through a pipe to a wellhead at the surface, deep holes are drilled down into the shale rock. These fractures are held open by an injected proppant, typically sand and release hydrocarbons. Fracking takes about three to five days. Since shale reserves are typically distributed horizontally rather than vertically, horizontal directional drilling method is employed.

Some of the impacts of Fracking on the environment are:

  • It consume large quantities of <em>fresh water</em>
  • The injection of recovered fracking water into underground disposal wells and the high pressure used to extract oil and gas from rock may cause <em>earthquakes</em>.
  • Fracking causes air and water pollution.
  • <em>Deforestation</em> caused by fracking has deep effects on the environment.

5 0
3 years ago
If the percent by mass is 4.0% and the mass of the solution is 200 g, what is the mass of solute in solution?
Inessa05 [86]

Answer:

8 grams.

Explanation:

When solving this type of problem, you need to find how many grams 4.0% of 200g will be equivalent to. You can do this by setting up an equation as such:

200 grams ×0.04 = 8 grams. (0.04 is equivalent to 4%)

4 0
4 years ago
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