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Len [333]
4 years ago
6

In which direction does a magnetic force act on an electron that is moving in the positive x-direction in a magnetic field point

ing in the positive z-direction?
A) any direction in the xy-plane
B) the negative y-direction
c) the negative x-direction
D) the positive y-direction


a particle with charge q is at rest when a magnetic field is suddenly turned on. The field
points in the z-direction. What is the direction of the net force acting on the charged particle?

a) In the z-direction.
b) There is no force on the particle.
c) In the y direction
d) In the x direction
Physics
1 answer:
alukav5142 [94]4 years ago
8 0
The best answer for the first question is B option ( the negative y-direction) which can be estimated by right hand rule.
And the best option for second question is also B option that there is no force on the particle.
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Answer: The bottom of the ladder is moving at 3.464ft/sec

Explanation:

The question defines a right angle triangle. Therefore using pythagorean

h^2 + l^2 = 10^2 = 100 ...eq1

dh/dt = -2ft/sec

dl/ dt = ?

Taking derivatives of time in eq 1 on both sides

2hdh/dt + 2ldl/dt = 0 ....eq2

Putting l = 5ft in eq2

h^ + 5^2 = 100

h^2 = 25 = 100

h Sqrt(75)

h = 8.66 ft

Put h = 8.66ft in eq2

2 × 8.66 × (-2) + 2 ×5 dl/dt

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3 years ago
If an object force of 50 N is used to move an object a distance of 20 m, what distance must the object be moved if the input for
steposvetlana [31]

Answer:

\ d_{out} = 100 \ m.

Explanation:

Given data:

F_{in} = 50 \ \rm N

F_{out} = 10 \ \rm N

d_{in} = 20 \ m

Let the distance traveled by the object in the second case be d_{out}.

In the given problem, work done by the forces are same in both the cases.

Thus,

W_{in} = W_{out}

F_{in}.d_{in} = F_{out}.d_{out}

\Rightarrow \ d_{out} = \frac{F_{in}.d_{in}}{F_{out}}

\ d_{out} = \frac{50 \times 20}{10}

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If you make multiple measurements of your height, you are likely to find that the results vary by nearly half an inch in either
Lisa [10]

Answer:

Height h= 1.7 m

Explanation:

Supposing we have to find height in meter.

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