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Gelneren [198K]
3 years ago
12

temperatura en la ciudad de la página madrugada y 2 grados bajo cero y a las 8 de la mañana sube a 6 grados y luego ya a las 10

de la mañana aumenta en 12 grados y sigue subiendo hasta llegar a los 21 al mediodía y de repente cada una granizada las 4 de la tarde bajando la temperatura en 15 Cuánto es la temperatura en La Paz a esa hora.​
Physics
2 answers:
vivado [14]3 years ago
8 0

Answer:

kjkjnklhklsehfiodxlfngioduherl

Explanation:

tino4ka555 [31]3 years ago
8 0
Huh English please...
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What voltage would be measured across the 45 ohm resistor?
Tamiku [17]
You would find the potential difference aka voltage, but more specifically it would be just the voltage that the resistor uses and not the whole circuit.

But if you want the voltage value it’s V=IR so whatever the current is multiply it by the 45 ohm resistor value
8 0
3 years ago
Read 2 more answers
Two coils that are separated by a distance equal to their radius and that carry equal currents such that their axial fields add
jok3333 [9.3K]

Answer:

When x = 2.8 cm, B_{x1} = 0.0265 T

When x = 5.5 cm, B_{x2} = 0.0209 T

when x = 7.3 cm, B_{x3} = 0.0169 T

When x = 11.0 cm, B_{x4} = 0.0103 T

Explanation:

According to Biot-Savart law,

B_{x} = \frac{N \mu_{o}IR^{2}  }{2(x^{2} +R^{2}  )^{3/2} }\\.......................(1)

R = 11.0 cm = 0.11 m

I = 17.0 A

N = 300 turns

\mu_{o}  = 4\pi  * 10^{-7} N/A^{2}

When x₁ = 2.8 cm = 0.028 m

B_{x1} = \frac{300 *(4\pi * 10^{-7} ) *  17 *0.11^{2}  }{2(0.028^{2} +0.11^{2}  )^{3/2} }\\B_{x1} = 0.0265 T

When x₂ = 5.5cm = 0.055 m

B_{x2} = \frac{300 *(4\pi * 10^{-7} ) *  17 *0.11^{2}  }{2(0.055^{2} +0.11^{2}  )^{3/2} }\\B_{x2} = 0.0209 T

When x₃ = 7.3 cm = 0.073 m

B_{x3} = \frac{300 *(4\pi * 10^{-7} ) *  17 *0.11^{2}  }{2(0.073^{2} +0.11^{2}  )^{3/2} }\\B_{x3} = 0.0169 T

When X₄ = 11.0 cm = 0.11 m

B_{x4} = \frac{300 *(4\pi * 10^{-7} ) *  17 *0.11^{2}  }{2(0.11^{2} +0.11^{2}  )^{3/2} }\\B_{x4} = 0.0103 T

4 0
3 years ago
What is not as soft as it's name implies in Anthropology forensic sciences?
irakobra [83]
No baby you baby no se que no se le da la gana de que se vaya de vacaciones yes because
5 0
3 years ago
How long does it take mercury to orbit the sun?
Oliga [24]
That is called the "Revolution Period of a planet" and one year on mercury equals to 88 days as compared to Earth

In short, Your Answer would be 88

Hope this helps!
3 0
3 years ago
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Approximately what core temperature is required before hydrogen fusion can begin in a star?
valkas [14]

Answer:

The temperature required is near about 3 million kelvin

Explanation:

The brilliance of the star results from the nuclear reaction that take place in the core of the star and radiate a huge amount of thermal energy resulting from the fusion of hydrogen into helium.

For this reaction to take place, the temperature of the star's core must be near about 3 million kelvin.

The hydrogen atoms collide and starts and the energy from the collision results in the heating of the gas cloud. As the temperature comes to near about 1.5\times 10^{7 {\circ}C, the nuclear fusion reaction takes place in the core of the gas cloud.

The huge amount of thermal energy from the nuclear reaction gives the gas cloud a brilliance resulting in a protostar.

8 0
3 years ago
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