Question

Two 3.7 microCoulomb charges are 0.8 m apart. How much energy (in milliJoule) went into assembling these two charges? Enter a number with one digit behind the decimal point.

Answer 1

Answer:

Explanation:

The potential energy of a system of two charges is given by the expression

$\frac{K\times Q_1\times Q_2}{R}$

Q₁ and Q₂ are two charges and R is distance between the charges.

Given Q₁ = Q₂ = 3.7 X 10⁻⁶ , R = .8 and K = 9 x 10⁹

Putting these values in the equation we have,

$[tex]\frac{9\times 10^9\times 3.7\times10^{-6} 3.7\times 10^{-6}}{.8}$[/tex]

Potential energy = 154.01 x 10⁻³ J

This energy have been spent to bring these repelling two charges at this close distance . The energy spent have been stored as potential energy here which has been calculated.