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cluponka [151]
3 years ago
15

Which two changes would decrease the electric force between two charged

Physics
1 answer:
Tema [17]3 years ago
7 0

Answer:

Increasing the separation distance between objects decreases the force of attraction or repulsion between the objects.

Explanation:

You might be interested in
Which of the following statements about electric field lines associated with electric charges is false? Electric field lines can
Tcecarenko [31]

Answer:

The false statement is 'Electric field lines form closed loops'.

Explanation:

  • Electric field lines originate from positive end and terminates at negative end,i.e., field lines are inward in direction to the negative charges and outward from the positive charges.
  • These lines when close together represents high intensity and when far apart shows low intensity of the field.
  • These lines do not intersect, as the tangent drawn on these lines provides us with the field direction and intersection of these lines means two field directions which is not possible.
  • These lines unlike magnetic field lines do not form closed loops as they do not turn around but originate at positive end and terminates at negative end which ensures no loop formation.
8 0
4 years ago
What happens to beaches over time?
Rama09 [41]

the answer is d i took the test be cause i go to a k12 onlie school


7 0
3 years ago
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2
timama [110]

Answer:

A

Explanation:

The acceleration of an object is directly proportional to its net force.

a =  \frac{f}{m}

4 0
3 years ago
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Do people use uranium for anything?
kati45 [8]

Answer:

kjlp;;

Explanation:

7 0
3 years ago
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James Cameron piloted a submersible craft to the bottom of the Challenger Deep, the deepest point on the ocean's floor, 11,000 m
Over [174]

Answer:

4.1\cdot 10^8 N

Explanation:

First of all, we need to find the pressure exerted on the sphere, which is given by:

p=p_0 + \rho g h

where

p_0 =1.01\cdot 10^5 Pa is the atmospheric pressure

\rho = 1000 kg/m^3 is the water density

g=9.8 m/s^2 is the gravitational acceleration

h=11,000 m is the depth

Substituting,

p=1.01\cdot 10^5 Pa + (1000 kg/m^3)(9.8 m/s^2)(11,000 m)=1.08\cdot 10^8 Pa

The radius of the sphere is r = d/2= 1.1 m/2= 0.55 m

So the total area of the sphere is

A=4 \pi r^2 = 4 \pi (0.55 m)^2=3.8 m^2

And so, the inward force exerted on it is

F=pA=(1.08\cdot 10^8 Pa)(3.8 m^2)=4.1\cdot 10^8 N

8 0
3 years ago
Read 2 more answers
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