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stealth61 [152]
3 years ago
7

After 252 days, a 12.0-g sample of the radioisotope scandium-46 contains only 1.5 g of the isotope. what is the half-life of sca

ndium-46
Chemistry
1 answer:
arsen [322]3 years ago
6 0
The half life of a scandium-46 is 84 days. The scandium-46<span> is used in oil refining as a tracer to monitor the oil movement and it emits </span><span>extremely high energetic gamma/beta radiation. So the half-life of the radioisotope scandium-46 is 84 days. The </span>Scandium 46 created by neutron activation, is a synthetic isotope of Scandium.
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Iodine is an elemnt, but is Iodide an element or it is a compound?
juin [17]

Answer: element

Explanation:

It only has one type of atom making it a element

5 0
3 years ago
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How many molecules of sulfur trioxide are in 78.0 grams?
Zarrin [17]
Molecular formula of sulfur trioxide is SO₃
Molar mass of SO₃ is -  32 + (16 x 3 ) = 80 g/mol
1 mol of any substance consists of 6.022 x 10²³ units. In 1 mol of SO₃ there are 6.022 x 10²³ molecules of SO₃
in 80 g of SO₃ - there are 6.022 x 10²³ molecules of SO₃
Therefore in 78 g of SO₃ - there are 6.022 x 10²³ /80 x 78 = 5.871 x 10²³ SO₃ molecules
7 0
3 years ago
Consider the following generic chemical equation: 2W + 3X → 3Y + Z When 5 units of W and 6 units of X are allowed to react, the
aliina [53]

Answer:

The answer to your question is letter b) X

Explanation:

Data

W = 5 units

X = 6 units

Chemical reaction

                              2W  + 3X   ⇒  3Y  +  Z

To determine which reactant is the limiting reactant, we must use proportions:

-Theoretical proportion   W / X  = 2 / 3 = 0.67

- Experimental proportion W / X = 5 / 6 = 0.83

As the experimental proportion is higher than the theoretical proportion, we conclude that the amount of W is higher in the experiment so the limiting reactant is X.

8 0
3 years ago
Glucose, c 6 h 12 o 6 , is a good source of food energy. when it reacts with oxygen, carbon dioxide and water are formed. how ma
melomori [17]

94.0 L if the reaction takes place under STP.

<h3>Explanation</h3>

The molar mass of glucose C₆H₁₂O₆ is

12.01 × 6 + 1.008 × 12 + 16.00 × 16.00 = 180.16 g / mol.

126 grams of glucose will contain 126 / 180.16 = 0.69939 mol of C₆H₁₂O₆. (To avoid rounding errors, keep a couple more digits than necessary.)

6 moles of CO₂ will be produced when 1 mole of C₆H₁₂O₆ is consumed. 0.69939 moles of C₆H₁₂O₆ will give rise to 4.196 mol of CO₂.

Assuming that the reaction takes place under STP, where T = 0 °C = 273 K and P = 1 atm. Each mole of any ideal gas will occupy a volume of 22.4 liters. The 4.196 moles of CO₂ will occupy 4.196 × 22.4 = 94.0 L. (The least significant number given is 126 g, the mass of glucose. This number has three significant figures. Thus, round the result to three significant figures.)

The volume of CO₂ can be found using the ideal gas law if the condition isn't STP. For example, T = 25 °C = 297 K and P = 1.00 × 10⁵ will lead to a different volume. By the ideal gas law,

V = (n · R · T) / (P)

where

  • V is the volume of the gas,
  • n is the number of moles of gas particles,
  • R is the ideal gas constant<em>,</em>
  • P is the pressure on the gas,
  • T is the absolute temperature of the gas (in degrees Kelvin.)

R = 8.314 × 10³ L · Pa / (K · mol)

Taking T = 297 K and P = 1.00 × 10⁵ Pa,

V = (4.196 × 8.314 × 10³ × 297 ) / (1.00 × 10⁵ ) = 104 L.

3 0
3 years ago
Logging involves people cutting down trees to acquire timber for uses such as
Fudgin [204]

Answer:

It would change the plant populations in the area.

It would change the plant populations in the area.

Explanation:

The answer choices are

A. It would remove all the soil from the area.

B. It would change the plant populations in the area.

C. It would remove all the populations from the area.

D. It would change the animal populations in the area.

It  wouldnt remove all populations or the soil but it would affect animals habitats and plant populations

7 0
3 years ago
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