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34kurt
3 years ago
6

Many industrial reactions, like the reaction of nitrogen gas (N2) and hydrogen gas (H2) to produce ammonia for fertilizers, have

a very slow reaction rate. What is one method that would speed up this reaction?
A. Add a catalyst to the reaction chamber.
B. Lower the pressure in the reaction chamber.
C. Increase the volume of the reaction chamber.
D. Decrease the temperature in the reaction chamber.
Chemistry
1 answer:
Jobisdone [24]3 years ago
8 0
Catalysts always quicken the experiment
You might be interested in
Which property can be used to tell gold and pyrite apart?
zubka84 [21]

Answer:

D. Malleability

Explanation:

Gold is made up of the element Au and it is a metal.

Pyrite is iron sulfide and it is a non-metal.

  • They have very similar appearance to such an extent that pyrite is widely called the fool's gold.
  • To distinguish between the two, we simply explore their metallic properties.
  • Gold is malleable. Pyrite is not. It will crumble under pressure.
6 0
3 years ago
Can I please get help with this question ‍♂️?
guapka [62]

Answer:

1.50 moles of POH or Potassium Hydroxide.

Explanation:

First of all, find the substance formula

The substance formula of Potassium Hydroxide is

KOH

Second of all, if you want to convert from grams to moles, you use molar mass of KOH

Third of all, find the molar mass of KOH.

K = 39.1 amu

O = 16.0 amu

H= 1.0 amu

Potassium has 1 atom, oxygen has 1 atom, and hydrogen has 1 atom.

So do this:

39.1(1) + 16.0(1) + 1.0(1) = 56.1

The molar mass of KOH is 56.1 g/mol.

Fourth of all, use dimensional analysis to show your work.

84.20 grams of KOH * 1 mol/56.1 g/mol

The moles will cancel out.

84.20 divided by 56.1 = 1.500892166

But I have to round my answer to two digits after the decimal points instead of using sig figs.

So I round to the hundredths place

1.500892166 = 1.50

So the final answer is 1.50 moles(don't forget the units) of POH.

Hope it helped!

3 0
3 years ago
If the initial temperature is 122 k, the final temperature is 53.3k, the temperature change is what?
Brut [27]

Answer:

its actually -68.7

Explanation:

correct on egd

3 0
4 years ago
A reaction mixture in a 3.67 l flask at a certain temperature initially contains a mixture of 0.763 grams of h2 and 96.9 grams o
Mrac [35]
The equilibrium constant is a value which represents the equilibrium of a reaction. It is a reaction quotient when the reaction reached equilibrium. The reaction in the system is expressed as:

<span>H2 + I2 = 2HI

we express Keq as follows:

Keq = [HI]^2 / [H2] [I2]

Where the terms represents the concentrations of the substances involved. THe concentrations are as follows:</span>

<span>H2 = 0.763 ( 1 / 18.02) / 3.67 = 0.0115 M</span>

<span>I2 = 96.9 ( 1 / 253.8) / 3.67 = 0.1040 M</span>

<span>HI (at equilibrium) = 90.4 ( 1 / 127.91) / 3.67 = 0.1956 M</span> 

<span>
By the ICE table, we can calculate the equilibrium concentrations,
        H2                       I2                           HI
I      0.0115              0.1040                        0
C      -x                        -x                         +2x
 -----------------------------------------------------------
E  0.0115-0.0963   0.1040-0.0963       0.1926 ===> x = 0.0963

Keq = (</span>0.1926<span>)^2 / (0.0077) (0.0848)
Keq = 56.81</span>

8 0
3 years ago
4. A gas with a pressure of 5.4 atm and at 25C is raised to a new temperature of 78C.
aleksandr82 [10.1K]

The answer for the following problem is mentioned below.

  • <u>Therefore the final pressure of the gas is 6.3 atm</u>

Explanation:

Given:

Initial pressure (P_{1}) = 5.4 atm

Initial temperature (T_{1}) = 25°C = 273 + 25 = 298 K

Final temperature (T_{2}) = 78°C = 273 + 78 = 351 K

To solve:

Final pressure (P_{2})

We know,

<em>From the ideal gas equation,</em>

P × V = n × R × T

Here from the above equation we can tell that ;

      <u><em> P ∝ T</em></u>

So;

we can write as;

  <em> </em>\frac{P}{T} \f<em> = constant</em>

(i.e.)

        \frac{P_{1} }{P_{2} } = \frac{T_{1} }{T_{2} }

Where;

P_{1} = Initial pressure of the gas

P_{2} = final pressure of the gas

T_{1} = initial temperature of the gas

T_{2} = final temperature of the gas

              \frac{5.4}{P_{2} }  = \frac{298}{351}

               P_{2} = \frac{5.4*351}{298}

               P_{2} = 6.3 atm

<u>Therefore the final pressure of the gas is 6.3 atm</u>

7 0
3 years ago
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