The dermal tissue is basically the outer part of the cell that protects the plant cell so in that case it would be the carbohydrate or cell wall. If you would put the choices it could have been a bit better :)
Answer:
Pre-zygotic, temporal separation
Explanation:
Reproductive isolation mechanism is of two types:
- Prezygotic mechanism
- Postzygotic mechanism
Prezygotic mechanism isolation occurs before fertilization and helpful in preventing formation of fertile offspring.
In frog external fertilization occurs. In the external fertilization, eggs and sperms are released in water and fertilization occur outside the water.
Prezygotic isolating mechanisms may include behavioral isolation, temporal isolation, mechanical isolation, gametic isolation and habitat isolation.
Temporal separation in reproduction is the sexual activity in the same geographical range but in different periods.
Therefore, the given reproductive isolation is pre-zygotic, temporal separation.
The total volume of water that would be removed will be 75 mL
<h3>Dilution equation</h3>
Using the dilution equation:
M1V1 = M2V2
In this case, M1 = 500 mL, V1 = 10.20 M, M2 = 12 M
Substitute:
V2 = 500 x 10.20/12
= 425 mL
The final volume in order to arrive at 12 M HNO3 would be 425 mL from the initial 500 mL. Thus, the total amount of water that will be removed by evaporation can be calculated as:
500 - 425 = 75 mL
More on dilution can be found here: brainly.com/question/7208939
Answer:
3.8 x 10⁵
Explanation:
For the equilibrium : 3NO(g) ⇌ N2O(g) + NO2(g), the equilibrium constant in the terms of the concentrations of the gases in mol/L is
Kc = (NO) (N2O)/ (NO) ³ where (NO), (N2O) , (NO2) are the concentrations of the gases in mol/L . So
K= (x mol/ 1 L) (x mol/1L) / (7.5 x 10⁻⁶ mol /1 L) ³
x = mol of NO and NO2 at equilibrium
we have that
K = x²/ 7.5 x 10⁻⁶ = 1.9 x 10¹⁶
x = √ (7.5 x 10⁻⁶ x 1.9 x 10¹⁶) = 3.8 x 10⁵
∴ (N2O) = 3.8 x 10⁵
