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scoundrel [369]
3 years ago
12

AL(OH)3+ HCI—> ALCL3 +H2O

Chemistry
1 answer:
UkoKoshka [18]3 years ago
4 0

Answer:

i dont know what you're asking here. But if you're asking what it is then:

Explanation:

Aluminum Hydroxide + Hydrogen Chloride = Aluminum Chloride + Water

Al and Oh3: Aluminum Hydroxide

H and Cl: Hydrogen Chloride

Al and Cl3: Aluminum Chloride

H2O: water

btw the first letter of every element should be capitalized. While the second and theird are lowercased.

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12. If a solution has a pH of 3, what would the pOH value of that solution be? *
butalik [34]

Answer:

The correct answer is pOH= 11

Explanation:

From the aqueous acid-base equilibrium we know that

pH + pOH = 14

If we know pH, we can calculate pOH as follows:

pOH = 14 - pH

In this problem, the solution has a pH of 3, so:

pOH = 14 - 3 = 11

8 0
2 years ago
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PLEASE HELP ASAP!!!!!!!! What type of plate boundary is this and what does it cause?
aliya0001 [1]

Answer:

divergent

Explanation:

Plates move apart at a divergent boundary

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3 years ago
what is the predicted order of fist ionization energies from highest to lowest for beryllium, calcium, magnesium, and stronium?
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2 years ago
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How many moles of Cu(OH)2 are soluble in 1L of sodium hydroxide (NaOH) when the pH is 8.23?
Morgarella [4.7K]

Answer:

4.96E-8 moles of Cu(OH)2

Explanation:

Kps es the constant referring to how much a substance can be dissolved in water. Using Kps, it is possible to know the concentration of weak electrolytes. Then, pKps is the minus logarithm of Kps.

Now, we know that sodium hydroxide (NaOH) is a strong electrolyte, who is completely dissolved in water. Therefore the pH depends only on OH concentration originating from NaOH. Let us to figure out how much is that OH concentration.

pH= -log[H]\\pH= -log (\frac{kw}{[OH]})

8.23 = - log(\frac{Kw}{[OH]} \\10^{-8.23} = Kw/[OH]\\ [OH] = Kw/10^{-8.23}

[OH]=1.69E-6

This concentration of OH affects the disociation of Cu(OH)2. Let us see the dissociation reaction:

Cu(OH)_2 -> Cu^{2+} + 2OH^-

In the equilibrum, exist a concentration of OH already, that we knew, and it will be added that from dissociation, called "s":

The expression for Kps is:

Kps= [Cu^{2+}] [OH]^2

The moles of (CuOH)2 soluble are limitated for the concentration of OH present, according to the next equation.

Kps= s*(2s+1.69E-6)^2

"s" is the soluble quantity of Cu(OH)2.

The solution for this third grade equation is s=4.96E-8 mol/L

Now, let us calculate the moles in 1 L:

moles Cu(OH)_2 = 4.96E-8 mol/L * 1 L = 4.96E-8 moles

7 0
3 years ago
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Answer:

I am pretty sure the correct answer is a reproductive system

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