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scoundrel [369]
3 years ago
12

AL(OH)3+ HCI—> ALCL3 +H2O

Chemistry
1 answer:
UkoKoshka [18]3 years ago
4 0

Answer:

i dont know what you're asking here. But if you're asking what it is then:

Explanation:

Aluminum Hydroxide + Hydrogen Chloride = Aluminum Chloride + Water

Al and Oh3: Aluminum Hydroxide

H and Cl: Hydrogen Chloride

Al and Cl3: Aluminum Chloride

H2O: water

btw the first letter of every element should be capitalized. While the second and theird are lowercased.

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The environment needs to what for natural selection to occur
allsm [11]

Answer:

i know 3, reproduction, organisms, and variations in traits

Explanation:

5 0
2 years ago
Read 2 more answers
The substances below are listed by increasing specific heat capacity value. Starting at 30.0 °C, they each absorb 100 kJ of ther
timama [110]

Answer:

Silver, 0.239 J/(g °C)

Explanation:

  • The heat change is related to specific heat as given by the formula;

Heat change = mass of substance × specific heat × change in temperature

  • Therefore; considering same amount of substance or equal masses and have the same initial temperature.
  • The change in temperature will be inversely proportional to the specific heat.
  • Therefore; the higher the specific heat lower the temperature change.
  • Hence,  the change in temperature will be highest for the substance with the lowest specific heat.

Therefore; the one that will increase in temperature the most is Silver

7 0
3 years ago
Assume that a firm has the following marginal benefit of pollution (denoted E for emissions, measured in tons): MB=150-5 E e. No
jeka57 [31]

Answer:

Explanation:

E)cost of pollution is reduction in benefit of the firms.

MB=150-5E,. MB=90-3E

E=30-MB/5. E=30-MB/3

Joint MB,

E=60-8MB/15

MB=112.5-1.875E

Total pollution reduction=24

Total pollution=60-24=36

MB=112.5-1.875*36=112.5-67.5=45

Firm 1

MB=150-5E.

45=150-5E.

E=-105/-5=21

Reduction=30-21=9

Firm 2,

MB=90-3E

45=90-3E

E=-45/-3=15

Reduction =30-15=15

So firm 2 is reducing 15 units of pollution and firm 1 reducing 9 units of pollution.

As each firm have to reduce 12 units of pollution but firm 2 reducing 3 units more while firm 1 reducing 3 less units.

So, firm 2 is selling 3 units of pollution emission permit to firm 1.

F)firm 1 reduce 9 units and firm 2 reduce 12 units of pollution after trade.

Total cost of pollution reduction will total Benefit reduction by pollution reduction.

MB=112.5 -1.875E

TB=112.5E-0.9375E^2

TB at E=60

TB=112.5*60-0.9375*60*60=6750-3375=3375

TB at E=36

TB=112.5*36-0.9375*36*36=4050-1215=2836

Total cost of pollution reduction=3375-2836=540

G)price of permit= cost of extra pollution reduction by firm 2 or total cost from 9 to 12 by firm 2

MB=90-3E

TB=90E- 1.5E^2

TB at E=18

TB=90*18 -1.5*18*18=1620-486=1134

TB at E=15

TB=90*15 -1.5*15*15=1350-337.5=1012.5

Permit price=1134-1012.5=121.5

Total cost to firm 2 =1134

Net total cost to firm 2=1134-121.5=1012.5

Total cost to firm 1=150E-2.5E^2=150*9-2.5*9*9=1350-202.5=1147.5

Net total cost=1147.5+121.5=1269

H) the total cost is lower in cap & trade policy is because the firm who has higher cost of pollution reduction is paying the other firm who has lower cost of pollution reduction to reduce more pollution ,so that his part of pollution reduction can be completed.

And the amount he is paying is equal to the amount that is cost of other firm of reducing additional pollution units.

So the cost the firm is lower as he is paying lower amount than if he reduce pollution by itself.

5 0
3 years ago
If 1.85 g of Mg(OH)2 reacts with 3.71 g of HCl,
Damm [24]
Both of them are a hope this helps
8 0
2 years ago
Please help me with these 3 questions with will be giving out brainiest
Anna71 [15]

Answer: All of them are true

5 0
2 years ago
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