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KonstantinChe [14]
3 years ago
10

Someone plz plz answer this hurry plz it

Chemistry
1 answer:
ziro4ka [17]3 years ago
8 0

Answer:

b

Explanation:

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A neutral atom with the electron configuration 2-8-6 would most likely form a bond with an atom having the configuration
Fittoniya [83]

Answer:

The configuration of the atom would be 2-8-2.

Explanation:

Any atom of an element combines with other element to complete its octet and become stable.

The electron configuration of the given atom is 2-8-6. That means the atom has 6 electrons in its outermost shell. To become stable the atom should have 8 electrons in its outermost shell. The given atom has 6 electrons so it either lose 6 electrons or gain 2 electrons to complete its octet.

But we know the atom having 5,6,7 electrons in its outermost shell they do not lose, they gain either 3 or 2 or 1 electrons to complete its octet.

So we say that atom with the electron configuration 2-8-6 bond with the atom having electron configuration 2-8-2.

8 0
3 years ago
. What is the mass of 23.56 moles of Glucose<br> ples of Glucose - C6H1206?
GaryK [48]

Answer:

4244.48 g to the nearest hundredth.

Explanation:

The molar mass of Glucose = 6*12.011 + 12*1.008+ 6*15.999

= 180.156.

So 23.56 moles = 180.156 * 23.56 =  4244.48 g

8 0
3 years ago
Someone plz help me
a_sh-v [17]

Answer:

A experimental investigation

3 0
2 years ago
What is the oxidation number of Nitrogen in HNO2? <br><br> +1<br> -1<br> +3<br> -3
WITCHER [35]
I believe the correct answer from the choices listed above is the third option. The <span>oxidation number of Nitrogen in HNO2 would be +3. It is calculated as follows:

1 + x + (-2)(2) = 0
x = +3

Hope this answers the question. Have a nice day.</span>
5 0
3 years ago
What mass of methane (CH4) gas occupies a volume of 0,462 L at 1atm and 273K
LiRa [457]

Explanation:

Since methane gas is at 1 atm and 273 K, it is at standard temperature and pressure(STP).

One mole of every gas occupies 22.4 dm^3 at STP, and vice versa. So,

22.4 dm^3 at STP of CH4=1 mol=12+4(1)=16 g

0.462 L(0.462 dm^3) at STP of CH4

=(16 g×0.462 dm^3)/22.4 dm^3

=0.33 g

6 0
3 years ago
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