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kodGreya [7K]
3 years ago
15

(Thermodynamics)

Chemistry
1 answer:
frutty [35]3 years ago
3 0

Answer:

3853 g

Step-by-step explanation:

M_r: 107.87

         16Ag + S₈ ⟶ 8Ag₂S; ΔH°f =  -31.8 kJ·mol⁻¹

1. Calculate the moles of Ag₂S

Moles of Ag₂S = 567.9 kJ × 1 mol Ag₂S/31.8kJ = 17.858 mol Ag₂S

2. Calculate the moles of Ag

Moles of Ag = 17.86 mol Ag₂S × (16 mol Ag/8 mol Ag₂S) = 35.717 mol Ag

3. Calculate the mass of Ag

Mass of g = 35.717 mol Ag × (107.87 g Ag/1 mol Ag) = 3853 g Ag

You must react 3853 g of Ag to produce 567.9 kJ of heat

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Explain why you would want to keep some, but not all, receipts as part of your financial records.
miss Akunina [59]

Answer:

Explanation:

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6 0
3 years ago
Read 2 more answers
Indicate if the following statements are TRUE (T) or FALSE (F):
Aleks [24]

Answer:

a) T

b) T

c) F

d) F

e) T

f) T

g) T

h) F

I) F

j) F

k) F

l) F

Explanation:

The w/v concentration is obtained from, mass/volume. Hence;

%w/v= 50/1000= 5%

In the %w/w we have;

25g/100 g = 25% w/w

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3 0
3 years ago
A gas occupies 4.30 Liters at STP. What volume does it occupy at 2.56 atm and 302
laiz [17]

Answer:

V₂ = 1.86 L

Explanation:

Given data:

Initial volume = 4.30 L

Initial pressure = 1 atm

Initial temperature = 273.15 K

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Final pressure = 2.56 atm

Solution:

According to general gas equation:

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V₂ = P₁V₁T₂ /T₁ P₂

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V₂ = 1298.6 atm.L.K / 699.26 K.atm

V₂ = 1.86 L

4 0
3 years ago
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